Hello, I'm trying to complete the following Discrete Maths questions. I've attached a screenshot of the questions.I've also attached a picture of the Laws Of The Predicate Calculus sheet we use.The number beside the question e.g. (13) represents the Law on the Predicate Calculus Sheet. PLEASE NOTE: The question title informs you up to which law on the sheet you can use. e.g. Using Laws of the Predicate Calculus 0–26, prove the following: You CANNOT use laws 27+ in this scenario. 1. Using Laws of the Predicate Calculus 0-26, prove the following:(27) [X ⇒ XV Y]"⇒V"2. Using Laws of the Predicate[XAY = X](28)Calculus 0-27, prove the following:"^⇒"3. Using Laws of the Predicate Calculus 0-28, prove the following:[XAY=XVY] 0123456788a91024252627282930313233= associative*= symmetric*= identity*= reflexivetrue1112131415161718V/A19 A/V20212223343536v symmetric*v associative*v idempotent*V/=*V/EBv/vv zeroGolden Rule*Asymmetric^ associative^ idempotent^ identityabsorption.0absorption.1A over=A/EEstrong MPreplacement→ definition*→ reflexive=> true⇒V1➡>>shuntingto A=⇒over=←=definition*44>>7LAWS OF THE PREDICATE CALCULUSfalse definition*over =*- neg-identity[(X=(Y=Z)) = ((X=Y) = Z)][X=Y=Y=X][X = true = X][X=X][true][Xv Y = YvX][Xv (YvZ) = (XVY) v Z][Xv X = X][Xv (Y=Z) = Xv Y = Xv Z][Xv (Y=Z=W) = Xv Y = XvZ = Xv W][Xv (YvZ) = (XVY) v (X v Z)][Xv true = true][X. Y = X = Y = Xv Y][XAY = YAX][XA (YAZ) = (X^ Y) ^ Z]E[X^X = X][X A true = X][XA (XVY) = X][XV (XAY) = X][XV (YAZ) = (XVY) A (XV Z)][XA (YV Z) = (X^Y) V (X^Z)][X. (Y=Z) = XAY = XAZ = X][XA (Y=Z=W) = XAY = X^ Z = X^ W][X^ (X= Y) = XAY][(X=Y) ^ (W = X) = (X=Y) ^ (W = Y)][X Y = Xv Y = Y][X⇒X][X→> true][X → Xv Y][X^ Y ⇒ X][XAY = Z = X=(Y=Z][X = Y = X^ Y=X][X➡ (Y=Z) = XAY=X^Z][X[XY = XA Y = Y]Y = Y⇒X][false = true][-(X=Y) = -X=Y][-X=X=false]postulates are decorated with a *

Answered: Image /qna-images/answer/d9790a45-2c7e-4dd9-b203-ff3aa6121c30.jpg

1. Using Laws of the Predicate Calculus 0-26, prove the following: [X⇒ XVY "⇒V" (27) 2. Using Laws of the Predicate Calculus 0-27, prove the following: (28) [XAY=X] "A⇒" 3. Using Laws of the Predicate Calculus 0-28, prove the following: [XAY=XVY

1. Using Laws of the Predicate Calculus 0-26, prove the following: [X⇒ XVY "⇒V" (27) 2. Using Laws of the Predicate Calculus 0-27, prove the following: (28) [XAY=X] "A⇒" 3. Using Laws of the Predicate Calculus 0-28, prove the following: [XAY=XVY

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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