1. The following molecule has a molecular formula of C,H10O. The IR and 'H-NMR spectra of the compound are below. Deduce the structure of the compound, justify your structure by assigning appropriate peaks in the IR and NMR spectra (on the spectra, if possible), and providing a short narrative describing what structural information each piece of data provided. 20- 35ee capillary fi ln betueen salt plates 2see 15e0 1800 AUENUBERS Copyright 1992 600.e -7500 -7000 es00 4000 ss00 -5000 -4500 -4000 -3500 -1000 -2500 -2000 1500 从 -1000 -100 TT 500

1. The following molecule has a molecular formula of C,H10O. The IR and 'H-NMR spectra of the compound are below. Deduce the structure of the compound, justify your structure by assigning appropriate peaks in the IR and NMR spectra (on the spectra, if possible), and providing a short narrative describing what structural information each piece of data provided. 20- 35ee capillary fi ln betueen salt plates 2see 15e0 1800 AUENUBERS Copyright 1992 600.e -7500 -7000 es00 4000 ss00 -5000 -4500 -4000 -3500 -1000 -2500 -2000 1500 从 -1000 -100 TT 500

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Show a structure for the compound C6H8 that has the following 13C NMR spectrum and explain how you got the answer.
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The NMR spectra for compound 1 were acquired in a 7.5 mg / 0.6 mL solution ofCDCl3 . The 1H and 13C peaks are also listedbelow. Provide a full analysis of the NMR spectra for compound 1. correct assignment of NMR spectra of both 13C spectra. correct rationalisation of 13C spectrum1H NMR (400 MHz, CDCl3) δ 7.73 (d, J = 9.5 Hz, 1H), 7.56 (ddd, J = 8.5, 7.5, 1.6 Hz, 1H),7.51 (dd, J = 7.5, 1.6 Hz, 1H), 7.36 (d, J = 8.5 Hz, 1H), 7.30 (dd, J = 8.5, 7.5 Hz, 1H), 6.45(d, J = 9.5 Hz, 1H).13C NMR (101 MHz, CDCl3) δ 160.79, 154.09, 143.43, 131.85, 127.87, 124.44, 118.86,116.94, 116.74.Note: There are two carbon peaks in the 13C spectrum that are so close together that they are not differentiable at the resolution in this experiment. you should be able to assign these peaks to one of two carbon atoms in 1.
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2. (Chapter 13 - Q58b) The compound whose H NMR spectrum is shown has the molecular formula C7H7B1. Follow the following questions to predict the unknown structure. Chem. shift Rel. area 2.31 1.50 701 1.00 7.35 1.00 TMS 10 7 6 O ppm 4 3 2 Chemical shift (8) e20s Cenge leaming 2(a) Degree of the unsaturation of this compound is= 2(b) The two distinct peaks in the aromatic region of the H NMR indicate that compound is .disubstituted = 2(c) The splitting pattern of the peak at 2.31 ő is = 2(d) The group that corresponds to the splitting pattern in 1(c) is = 2(e) This compound has the plane of symmetry Yes or No = 2(f) The name of the unknown compound = Intensity
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