1. The following data shows the results of the liquid limit and plastic limit test using Casagrande cup method. Calculate the following: (Hint: Solve the moisture content of each test) a. Liquid Limit b. Plasticity Index c. Liquidity Index Liquid Limit Test: TEST NO. No. of Blows Wt. of Wet Soil + Container Wt. of Dry Soil + Container Wt. of Container Plastic Limit Test: TEST NO. Wt. of Wet Soil + Container Wt. of Dry Soil + Container Wt. of Container Natural Water Content: TEST NO. Wt. of Wet Soil + Container Wt. of Dry Soil + Container Wt. of Container 1 35 22.46 g 19.44 g 12.76 g 1 22.10 g 20.42 g 13.07 g 1 17.94 g 14.84 g 7.84 g 2 21 21.33 g 18.75 g 13.06 g 2 21.77 g 20.19 g 13.28 g 2 17.39 g 14.36 g 7.50 g 3 16 21.29 g 18.78 g 13.26 g

1. The following data shows the results of the liquid limit and plastic limit test using Casagrande cup method. Calculate the following: (Hint: Solve the moisture content of each test) a. Liquid Limit b. Plasticity Index c. Liquidity Index Liquid Limit Test: TEST NO. No. of Blows Wt. of Wet Soil + Container Wt. of Dry Soil + Container Wt. of Container Plastic Limit Test: TEST NO. Wt. of Wet Soil + Container Wt. of Dry Soil + Container Wt. of Container Natural Water Content: TEST NO. Wt. of Wet Soil + Container Wt. of Dry Soil + Container Wt. of Container 1 35 22.46 g 19.44 g 12.76 g 1 22.10 g 20.42 g 13.07 g 1 17.94 g 14.84 g 7.84 g 2 21 21.33 g 18.75 g 13.06 g 2 21.77 g 20.19 g 13.28 g 2 17.39 g 14.36 g 7.50 g 3 16 21.29 g 18.78 g 13.26 g

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter5: Classification Of Soil

Section: Chapter Questions

Problem 5.10P

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2a. The following data was obtained from Liquid Limit Test conducted at a Soil Lab. Using the data given in Table 01, determine the following; Liquid Limit Determination Specimen No. No. of Blows Wt. of Container Wt. of Container + Wet Soil Wt. of Container + Dry Soil i. ii. Unit 1 14 (g) 7.17 (g) 27.97 (9) 21.37 2 20 7.37 27.37 21.27 3 28 7.77 28.47 22.37 4 32 10.97 30.17 24.67 I Determine the Liquid Limit and Flow Index If Plastic Limit of this soil is 22. Classify the soil based on BS Soil Classification system. 5 39 7.27 26.57 21.17
Paragraph Liquid Limit Determination Specimen No. No. of Blows Wt. of Container Wt. of Container + Wet Soil Wt. of Container + Dry Soil İ. ii. a. The following data was obtained from Liquid Limit Test conducted at a Soil Lab. Using thedata given in Table 01, determine the following; Table 01: Liquid Limit Test data for the particular soil sample Unit (g) (g) (g) 1 14 7.13 27.93 T Body Text T Heading 1 T List Para... T No Spac... 21.33 2 20 7.33 27.33 21.23 3 28 7.73 28.43 22.33 F/QAP/021/004 4 32 10.93 Styles 30.13 24.63 5 39 7.23 26.53 21.13 Determine the Liquid Limit and Flow Index If Plastic Limit of this soil is 22. Classify the soil based on BS Soil Classification system. T Norma
The following data was obtained from standard proctor compaction test: Weight of Weight of mold+ Weight of mold+ base compacted moist plate, w1, (g Moist Moisture Dry unit unit Test No. moist content, weight, soil+ base plate, compacted weight, W2, (g) We(%) soil, (g/cm3) Ymoist (g/cm3) W2-W1, (g) 1 15780 20700 15780 21160 3 15780 21300 15780 21360 15780 21400 Water content determination: wi(mass of empty can) W2(mass of can+ moist soil) W3(mass of can+ dry soil) Test No. Water content (W%) 1. 15.34 73.18 71.06 2. 15.34 84.45 80.52 3 12.66 59.58 56.64 4 16.84 88.91 83.61 12.66 98.1 90.33 Volume of mold = 944cm3 Calculate the maximum dry unit weight and O.M.C (show all your calculations and drawing)
The results of a Standard Proctor test are given in the following table. Moist Weight of Wet Sol Moisture Content in the mold (Ib) Trial (%) 26 4.08 28 4.12 30 4 4,18 32 Determine: 1. Maximum dry unit weight in Ib/ft^3 (4 decimal places) 2. Optimum water content in % (4 decimal places)
The resulting of the Standard Proctor Test is as follows: Vol. of Proctor Mold (cu.m) Wt. of wet soil in mold (kg) Moisture (%) 943.3 1.76 12 943.3 1.86 14 943.3 1.92 16 943.3 1.95 18 943.3 1.93 20 943.3 1.90 22 a. Determine the maximum dry unit weight of compaction b. Determine the optimum moisture content
2. The resulting of the Standard Proctor Test is as follows: Vol. of Proctor Mold Wt. of wet soil in mold Moisture (cu.m) (kg) (%) 943.3 1.76 12 943.3 1.86 14 943.3 1.92 16 943.3 1.95 18 943.3 1.93 20 943.3 1.90 22 a. Determine the maximum dry unit weight of compaction b. Determine the optimum moisture content
Afalling-head permeability test is performed on a fine-grained soil. The soil sample has a length of 120 mm and a cross-sectional area of 600 mm2. The water in the standpipe flowing into the soil is 0.60 m above the top of the sample at the start of the test. It falls 50 mm in 30 minutes. The standpipe has a cross-sectional area of 200 mm2. (a) Make a sketch of the described conditions. (b) What is the coefficient of permeability in millimeters per second? (c) What is the coefficient of permeability in feet per minute? (d) On the basis of the calculated value for khyd, what is the probable soil type?
PLS SHOW YOUR COMPLETE SOLUTIONGiven the laboratory results of the Atterberg Limits Test in the following figure, plot the water content versus the number of blows. a. Determine the nearest value to the Liquid Limit of soil. Answer: 47.1%b. Determine the nearest value to the Plastic Limit of soil. Answer: 38.34%c. Determine the nearest value to the Liquidity Index of soil. Answer: 1.55
Subj: civil engineering / soil mechanics The volume of soil sample measured before oven drying is 120 cm3. The dried weight of the soil sample is 122 g. The percent passing of No. 200 sieve is 63% and the group index is 12.82. The liquidity index and plastic limit are 1.25 and 7.6%, respectively. If the specific gravity of soil is 2.70, compute the following: a. Void ratio b. Dry unit weight c. Dry unit weight at zero air voids
Solve a and b