1. The first step involves 2. H-CI is polarised: H is the 3. The alkene behaves as a 4. In step 1, electron density flows from the bond breaks and forms 5. The intermediate species is a end, and Cl is the and HCI behaves as a to the end the H-CI

1. The first step involves 2. H-CI is polarised: H is the 3. The alkene behaves as a 4. In step 1, electron density flows from the bond breaks and forms 5. The intermediate species is a end, and Cl is the and HCI behaves as a to the end the H-CI

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Q.2 ch

Protonation of the alkene
carbocation
nucleophile
H of the H-CI
carbanion
Addition of CI-
Cl of the H-CI
CI-
middle of the alkene pi-bond
delta -
H+
fast
a C atom of the alkene
electrophile
slow
delta +

1. The first step involves
2. H-CI is polarised: H is the
3. The alkene behaves as a
4. In step 1, electron density flows from the
bond breaks and forms
5. The intermediate species is a
6. In the second step of the reaction the nucleophilic
7. The first step is the
the reaction
yu
H
H
+ H-A
Intermediate
XXH
се
H
end, and Cl is the
and HCI behaves as a
to the
step and the second step the
end
attacks the intermediate
the H-CI
step of

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