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1. The equilibrium constant for the following reaction at 600 °C is determined to be Kc = 0.495: H₂O(g) + CO(g) ≤ H₂(g) + CO₂(g) Calculate the number of H₂ moles that are present at equilibrium if a mixture of 0.400 mole CO and 0.500 mole H₂O is heated to 600°C in a 10.0-L container.

1. The equilibrium constant for the following reaction at 600 °C is determined to be Kc = 0.495: H₂O(g) + CO(g) ≤ H₂(g) + CO₂(g) Calculate the number of H₂ moles that are present at equilibrium if a mixture of 0.400 mole CO and 0.500 mole H₂O is heated to 600°C in a 10.0-L container.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Please help me solve the reactions using extent reaction method and ICE method (both answers would be equal at the end). I will give an absolute thumbs up. Step by step please. 


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1. The equilibrium constant for the following reaction at 600 °C is determined to be Kc = 0.495: H₂O(g) + CO(g) → H₂(g) + CO₂(g) Calculate the number of H₂ moles that are present at equilibrium if a mixture of 0.400 mole CO and 0.500 mole H₂O is heated to 600°C in a 10.0-L container.
Transcribed Image Text:1. The equilibrium constant for the following reaction at 600 °C is determined to be Kc = 0.495: H₂O(g) + CO(g) → H₂(g) + CO₂(g) Calculate the number of H₂ moles that are present at equilibrium if a mixture of 0.400 mole CO and 0.500 mole H₂O is heated to 600°C in a 10.0-L container.
2. The equilibrium constant Kc for the following reaction at 800°C is 3.74 x 105 H₂(g) + 1₂(g) → 2HI(g) If 6.25 moles of HI were initially added to a 15.0-L empty vessel, what would the concentrations of H₂, I2, and HI be at equilibrium.
Transcribed Image Text:2. The equilibrium constant Kc for the following reaction at 800°C is 3.74 x 105 H₂(g) + 1₂(g) → 2HI(g) If 6.25 moles of HI were initially added to a 15.0-L empty vessel, what would the concentrations of H₂, I2, and HI be at equilibrium.
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