1. The enzyme you are studying uses the substrate pictured at right. An inhibitor box in the freezer contains two tubes labeled Inhibitor #1 and Inhibitor #2, along with the structures of the compounds contained within them and their respective Ki. Which one is more likely to be the non-competitive inhibitor? Inhibitor #1 K₁ = 10 μM m OH CH₂OH OH OH Inhibitor #2 K₁ = 50 μM m Briefly Justify: OH CH₂OH OH -O. OH ОН Substrate
1. The enzyme you are studying uses the substrate pictured at right. An inhibitor box in the freezer contains two tubes labeled Inhibitor #1 and Inhibitor #2, along with the structures of the compounds contained within them and their respective Ki. Which one is more likely to be the non-competitive inhibitor? Inhibitor #1 K₁ = 10 μM m OH CH₂OH OH OH Inhibitor #2 K₁ = 50 μM m Briefly Justify: OH CH₂OH OH -O. OH ОН Substrate
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
Related questions
Question

Transcribed Image Text:1. The enzyme you are studying uses the substrate pictured at right. An
inhibitor box in the freezer contains two tubes labeled Inhibitor #1 and
Inhibitor #2, along with the structures of the compounds contained
within them and their respective Ki. Which one is more likely to be the
non-competitive inhibitor?
Inhibitor #1
K₁ = 10 μM
m
CH₂OH
OH -0, $
OH
OH
Inhibitor #2
K₁ = 50 μM
Briefly Justify:
OH
CH₂OH
OH
OH
OH
Substrate
Expert Solution

Enzyme Inhibition
Enzyme inhibition is when a inhibitor bind to the enzyme at the active site or another site, which results in either decrease in enzyme's catalytic activity or enzyme's catalytic activity coming to a complete halt.
Enzyme inhibition can be reversible or irreversible.
Reversible inhibition is when the inhibitor binds reversibly to the enzyme. It can be competitive, un-competative or non-competative.
Irreversible inhibition is when inhibitor binds covalently to the enzyme and ends enzyme catalysis.
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