1. Modelling non-zero count data Count data is quite often only recorded when at least one event happens (i.e. zero count events are not recorded). For example, the numbers below give the alcohol units consumed by a certain mathematics professor on the last 13 times he went out drinking: 16321 3 3 9 3 2 11 2 Such count data can be modelled using zero-truncated models such as the zero-truncated Poisson model which has mass function:

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1. Modelling non-zero count data
Count data is quite often only recorded when at least one event happens (i.e.
zero count events are not recorded). For example, the numbers below give
the alcohol units consumed by a certain mathematics professor on the last 13
times he went out drinking:
16 3 2 1 3 39 3 2 1 1 2
Such count data can be modelled using zero-truncated models such as the
zero-truncated Poisson model which has mass function:
Pr(X = x) = c
forx = 1,2,...
x!
%3D
where c = (1-e)" takes account of having Pr(X = 0) = 0.
c) Show that all the non-centered positive moments of the zero-truncated
Poisson distribution, E(X^) for k>0, are equal to the respective
moments of the un-truncated Poisson distribution multiplied by c;
d) Use this result to find the mean number of alcohol units E(X) and the
probability that the professor will drink nine units of alcohol Pr(X-9)
ife = 2. Does this estimate of 0 = 2 seem likely given the sample of
data?
Transcribed Image Text:1. Modelling non-zero count data Count data is quite often only recorded when at least one event happens (i.e. zero count events are not recorded). For example, the numbers below give the alcohol units consumed by a certain mathematics professor on the last 13 times he went out drinking: 16 3 2 1 3 39 3 2 1 1 2 Such count data can be modelled using zero-truncated models such as the zero-truncated Poisson model which has mass function: Pr(X = x) = c forx = 1,2,... x! %3D where c = (1-e)" takes account of having Pr(X = 0) = 0. c) Show that all the non-centered positive moments of the zero-truncated Poisson distribution, E(X^) for k>0, are equal to the respective moments of the un-truncated Poisson distribution multiplied by c; d) Use this result to find the mean number of alcohol units E(X) and the probability that the professor will drink nine units of alcohol Pr(X-9) ife = 2. Does this estimate of 0 = 2 seem likely given the sample of data?
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