1. List CollectionComplete the program that will reverse each word on the given stringEfun main() {print("Enter a string: ")val str = rdLn()val words str.split("")val newStr wordReverse (words)println("new string length: ${newStr.length}")println(newStr)}fun wordReverse (words: List): String{//List Manipulation Code Here}private fun rdLn() = readLine()!!private fun rdInt() = rdLn().toInt ()Enter a string: the quick brown foxnew string length: 19eht kciuq nworb xofEnter a string: there are 10 boysnew string length: 17ereht era 01 syobEnter a string: red blue @#$% yellownew string length: 20der eulb %$#@ wolleyExample output 1:Example output 2:Example output 3:

1. List Collection Complete the program that will reverse each word on the given string B fun main() { print("Enter a string: ") val str = rdLn() val words = str.split("") val newStr = wordReverse (words) println("new string length: ${newStr.length}") println(newStr) } fun wordReverse (words: List): String{ //List Manipulation Code Here

1. List Collection Complete the program that will reverse each word on the given string B fun main() { print("Enter a string: ") val str = rdLn() val words = str.split("") val newStr = wordReverse (words) println("new string length: ${newStr.length}") println(newStr) } fun wordReverse (words: List): String{ //List Manipulation Code Here

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Split - Filter - Sort romeo = 'But soft what light through yonder window breaks It is the east and Juliet is the sun Arise fair sun and kill the envious moon Who is already sick and pale with grief Split the long string romeo into a list of words using the split function. For each word, check to see if the word is already in a list. If the word is not in the list, add it to the list. When the program completes, sort and print the resulting words in alphabetical order. The result will be like this: ['Arise', 'But', 'It', 'Juliet', "Who', 'already', 'and', 'breaks', 'east', 'envious', 'fair', 'grief', 'is', 'kill', "'ight', 'moon', 'pale', 'sick', 'soft', 'sun', 'the', 'through', 'what', 'window', 'with', 'yonder']
Static Length, Limited Dynamic Length, and Dynamic Length String implementations have what advantages and disadvantages?
-Write a statement that assigns the list of seasons of the year to the variable seasons in the following order in Python: Winter Spring Summer Fall -Write one statement that uses the in operator to test if the element 'surfing' is present in list listActivities and print the results. -Using the del keyword and/or the slicing operator:, delete the 3rd through the 5th element from the list listTemps. You've been provided a list named myLst, of six integers. Set the fourth element's value to 7.
zain IQ لا توجد خدمة docs.google.com Q #includeusing namespace std; int main (){ int a[100]; int i, n „large ;cout>a[i]; }large =a[0];for (i=O ; i<=99 ; i++)if (larg < a[i])larg = ali] ;cout<<" largest value in the array = "<< larg ;return 0;} true False The general form of (One- Dimensional Arrays) is:Type Array Name [number of elements] * True False Char a[5][6]; *
Help me fix all the error in this programme #include <iostream>#include <iomanip>#include <ctype.h>#include <string.h> using namespace std; struct nodeBankAccount { char bank_acc_name[30]; string bank_acc_num; double bank_acc_bal; nodeBankAccount*link;}; nodeBankAccount *head, *rear;nodeBankAccount *current;nodeBankAccount *newNode;nodeBankAccount *deleteBank;nodeBankAccount *previous;nodeBankAccount *found; void searchBankAccount(){ char searchName[30]; int searchNumber = 0; int searchOption; char answer; int searchNumber_No = 0; found = NULL; current = head; if(current == NULL) { cout<<"\n\n List is empty!!!\n"; cout<< "Cannot perfom search operation \n\n"; }else{ do { cout << "\n\tSearch record\n"; cout << "\t\tSearch Menu\n"; cout<<"\nEnter 1 to search by Bank Account Name\n: ";…
Creat a void fuction void myUpdate(string dictionary[], int wordCount, string oldWord, string newWord); Where it will replace the oldWord with the newWord, if the search is successful
Lab Goal : This lab was designed to teach you more about list processing and algorithms.Lab Description : Write a program that will search a list to find the first odd number. If an odd number is found, then find the first even number following the odd number. Return the distance between the first odd number and the LAST even number. Return -1 if no odd numbers are found or there are no even numbers following an odd number
int tryMe(int x[], int size); void main() { int list[75]; cout<< tryMe (list, 75); } valid invalid
#include <bits/stdc++.h>using namespace std; int main() { string str; cout << "Enter a string: "; getline (cin, str); for(int i=0; i<str.length(); i++){ if(str[i]=='a' || str[i]=='e' || str[i]=='i' || str[i]=='o' || str[i]=='u' || str[i]=='A' || str[i]=='E' || str[i]=='I' || str[i]=='O' || str[i]=='U'){ str[i] = '*'; } } cout<<"Resulting string: "<<str; return 0; WHAT DOES THE FOR LOOP MEAN HERE? PLEASE EXPLAIN for(int i=0; i<str.length(); i++){
Bubble Sort HouseholdSize.py 2 HouseholdSize.py - This program uses a bubble sort to arrange household sizes Summary in descending order and then prints the mean and median 3 4 household size. In this lab, you will complete a Python program that uses a list to store data for the village of 5 Input: Interactive. Marengo. 6 Output: Mean and median household size. 8 The village of Marengo conducted a census and collected records that contain household 9 # Initialize variables. 10 householdSizes = [] # Array used to store household sizes. 11 numSizes = 0 data, including the number of occupants in each household. The exact number of household records has not yet been determined, but you know that Marengo has fewer than 300 households. 12 total = 0.0 13 mean = 0.0 The program is described in Chapter 8, Exercise 5, in Programming Logic and Design. The 14 median = 0.0 15 program should allow the user to enter each household size and determine the mean and 16 # Input household size 17…