1. In the figure below, Q₁ (-6 μC) by Q₂ (2 μC) are shown. Use k=9x109 Nm²/c². Q1 x=0 Q2 x=3cm x 4cm X Using Part 1, the electric field due to Q₁ and Q₂ at x = 3 cm should have looked like this. Q₂ is closer to the point x=3 cm compared to Q₁. Therefore, | E₂ | > |E₁|. Both fields point in the negative x- direction. E₁ E₂ x=3cm (a) Calculate the electric field E₁ due to Q₁ at x = 3 cm. E₁:2 N/C (b) Calculate the electric field E₂ due to Q₂ at x = 3 cm. E₂: 9 N/C (c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂. Enet: 09 N/C
1. In the figure below, Q₁ (-6 μC) by Q₂ (2 μC) are shown. Use k=9x109 Nm²/c². Q1 x=0 Q2 x=3cm x 4cm X Using Part 1, the electric field due to Q₁ and Q₂ at x = 3 cm should have looked like this. Q₂ is closer to the point x=3 cm compared to Q₁. Therefore, | E₂ | > |E₁|. Both fields point in the negative x- direction. E₁ E₂ x=3cm (a) Calculate the electric field E₁ due to Q₁ at x = 3 cm. E₁:2 N/C (b) Calculate the electric field E₂ due to Q₂ at x = 3 cm. E₂: 9 N/C (c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂. Enet: 09 N/C
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![1. In the figure below, Q₁ (-6 μC) by Q₂ (2 μC) are shown.
Use k=9x109 Nm²/c².
Q1
x=0
Q2
x=3cm x 4cm
X
Using Part 1, the electric field due to Q₁ and Q₂ at x = 3 cm should have looked like this. Q₂ is closer
to the point x=3 cm compared to Q₁. Therefore, |E₂| > |E₁. Both fields point in the negative x-
direction.
E₁
E₂ x 3cm
(a) Calculate the electric field E₁ due to Q₁ at x = 3 cm.
E₁:2
N/C
(b) Calculate the electric field E₂ due to Q₂ at x = 3 cm.
E₂: 9
N/C
(c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂.
Enet: 09
N/C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd4f4b624-9180-41b5-94fa-c093ec7455d7%2F1f545548-3408-430b-b414-35f684b8aacd%2Fefcjy9h_processed.png&w=3840&q=75)
Transcribed Image Text:1. In the figure below, Q₁ (-6 μC) by Q₂ (2 μC) are shown.
Use k=9x109 Nm²/c².
Q1
x=0
Q2
x=3cm x 4cm
X
Using Part 1, the electric field due to Q₁ and Q₂ at x = 3 cm should have looked like this. Q₂ is closer
to the point x=3 cm compared to Q₁. Therefore, |E₂| > |E₁. Both fields point in the negative x-
direction.
E₁
E₂ x 3cm
(a) Calculate the electric field E₁ due to Q₁ at x = 3 cm.
E₁:2
N/C
(b) Calculate the electric field E₂ due to Q₂ at x = 3 cm.
E₂: 9
N/C
(c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂.
Enet: 09
N/C
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