1. In the figure below, Q₁ (-6 μC) by Q₂ (2 μC) are shown. Use k = 9x10⁹ Nm²/C². Q1 x=0 Q2 x=3cm x=4cm X Using Part 1, the electric field due to Q₁ and Q₂ at x = 3 cm should have looked like this. Q₂ is closer to the point x=3 cm compared to Q₁. Therefore, |E₂|> |E₁|. Both fields point in the negative x- direction. E₁ E₂ x 3cm (a) Calculate the electric field E, due to Q₁ at x = 3 cm. E₁: N/C (b) Calculate the electric field E₂ due to Q₂ at x = 3 cm. E₂: N/C (c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂. Enet: N/C Hint: Don't forget the sign of the electric fields.
1. In the figure below, Q₁ (-6 μC) by Q₂ (2 μC) are shown. Use k = 9x10⁹ Nm²/C². Q1 x=0 Q2 x=3cm x=4cm X Using Part 1, the electric field due to Q₁ and Q₂ at x = 3 cm should have looked like this. Q₂ is closer to the point x=3 cm compared to Q₁. Therefore, |E₂|> |E₁|. Both fields point in the negative x- direction. E₁ E₂ x 3cm (a) Calculate the electric field E, due to Q₁ at x = 3 cm. E₁: N/C (b) Calculate the electric field E₂ due to Q₂ at x = 3 cm. E₂: N/C (c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂. Enet: N/C Hint: Don't forget the sign of the electric fields.
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
Transcribed Image Text:1. In the figure below, Q₁ (-6 µC) by Q₂ (2 μC) are shown.
Use k = 9x10⁹ Nm²/c².
Q1
x=0
x=3cm
Q2
x=4cm
X
Using Part 1, the electric field due to Q₁ and Q₂ at x = 3 cm should have looked like this. Q₂ is closer
to the point x=3 cm compared to Q₁. Therefore, |E₂|> |E₁|. Both fields point in the negative x-
direction.
E₁
E₂ x=3cm
(a) Calculate the electric field E₁ due to Q₁ at x = 3 cm.
E₁:
✔N/C
(b) Calculate the electric field E₂ due to Q₂ at x = 3 cm.
E₂:
N/C
(c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂.
Enet
N/C
Hint: Don't forget the sign of the electric fields.
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