In a city, it is estimated that the maximum temperature in June is normally distributed with a mean of 28º and a standard deviation of 5.4°. Calculate the number of days in this month in which it is expected to reach a maximum of between 22° and 31°.
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1. In a city, it is estimated that the maximum temperature in June is
2. The mean weight of 800 college students is 56 kg and the standard deviation is 5 kg. Assuming that the weight is normally distributed, determine how many students weigh:
a. Between 60 kg and 70 kg.
b. More than 68 kg.
3. Several intelligence tests follow a normal distribution with a mean of 100 and a standard deviation of 15.
a. Determine the percentage of the population that would obtain a score between 95 and 110.
b. For a population of 2,500, how many are expected to have a score above 125?
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- A ski gondola carries skiers to the top of a mountain. Assume that weights of skiers are normally distributed with a mean of 182 lb and a standard deviation of 38 lb. The gondola has a stated capacity of 25 passengers, and the gondola is rated for a load limit of 3500 lb. Complete parts (a) through (d) below. a. Given that the gondola is rated for a load limit of 3500 Ib, what is the maximum mean weight of the passengers if the gondola is filled to the stated capacity of 25 passengers? The maximum mean weight is Ib. (Type an integer or a decimal. Do not round.) b. If the gondola is filled with 25 randomly selected skiers, what is the probability that their mean weight exceeds the value from part (a)? The probability is. (Round to four decimal places as needed.) c. If the weight assumptions were revised so that the new capacity became 20 passengers and the gondola is filled with 20 randomly selected skiers, what is the probability that their mean weight exceeds 175 lb, which is the…Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P70, the 70-percentile. This is the temperature reading separating the bottom 70% from the top 30%.P70 = °CAssume that thermometer readings are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.) Between 1.50 and 2.25 Click to view page 1 of the table. Click to view page 2 of the table. Draw a sketch. Choose the correct graph below. O A. The probability of getting a reading between 1.50°C and 2.25°C is (Round to four decimal places as needed.) d Normal Table (Page 2) .00 Standard Normal (z) Distribution: Cumulative Area from the LEFT .5000 5398 5793 .6179 .6554 .6915 7257 .7580 7881 .8159 .8413 8643 .8849 .9032 9192 9332 9452 .9554 .9641 9713 9772 .9821 9861 0007 .01 5040 5438 5832 6217 .6591 z=1.50 z=2.25 6950 7291 .7611 7910 .8186 .8438 8665 8869 9049 9207 9345 9463 .9564 9649 .9719 9778 9826 9864 .02 5080 5478 5871 6255 6628 .6985 7324 7642 7939 .8212 8461 8686 8888 .9066 9222 9357 9474 .9573 9656…