A patient has a body temperature of 99.90° F. In general, human body temperatures have a mean of 98.20° F and a standard deviation of 0.62º. A. Find the z-score corresponding to the given value. Type your answer in the space provided. z= B. Find the body temperature separating the lower bound of usual human body temperatures with unusual human body temperatures. Type your answer in the space provided. C. Find the body temperature separating the upper bound of usual human body temperatures with unusual human body temperatures. Type your answer in the space provided. D. Is the test score given not usual or unusual? Type your answer in the space provided. Round each answer to the nearest hundredth, as needed. (Do not enter °F in any of the blanks.) °F °F

A patient has a body temperature of 99.90° F. In general, human body temperatures have a mean of 98.20° F and a standard deviation of 0.62º. A. Find the z-score corresponding to the given value. Type your answer in the space provided. z= B. Find the body temperature separating the lower bound of usual human body temperatures with unusual human body temperatures. Type your answer in the space provided. C. Find the body temperature separating the upper bound of usual human body temperatures with unusual human body temperatures. Type your answer in the space provided. D. Is the test score given not usual or unusual? Type your answer in the space provided. Round each answer to the nearest hundredth, as needed. (Do not enter °F in any of the blanks.) °F °F

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Assume that the mean height of women in the United States is 64.5 inches, with a standard deviation of 2.5 inches. A particular woman is 63 inches tall. Find the z-score of her height. (Round to two decimal places.)
Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the probability that a randomly selected thermometer reads between −1.55 and −0.17 and draw a sketch of the region. Click to view page 1 of the table. LOADING... Click to view page 2 of the table. LOADING... Sketch the region. Choose the correct graph below. A. -0.17-1.55 A graph with a bell-shaped curve, divided into 3 regions by 2 lines from top to bottom, both on the left side. The region between the 2 lines is shaded. Moving from left to right, the z-axis below the first line is labeled negative 1.55. The z-axis below the second line is labeled negative 0.17. B. -0.17-1.55 A graph with a bell-shaped curve, divided into 3 regions by 2 lines from top to bottom, both on the left side. Moving from left to right, the regions left of the second line are shaded. The z-axis…
Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. Assume 2.7% of the thermometers are rejected because they have readings that are too high and another 2.7% are rejected because they have readings that are too low. Draw a sketch and find the two readings that are cutoff values separating the rejected thermometers from the others. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents the region in which thermometers are rejected? Choose the correct graph below. В. D. The cutoff values are degrees. (Use a comma to separate answers as needed. Round to two decimal places as needed.)
Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. Assume 3.4% of the thermometers are rejected because they have readings that are too high and another 3.4% are rejected because they have readings that are too low. Draw a sketch and find the two readings that are cutoff values separating the rejected thermometers from the others. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents the region in which thermometers are rejected? Choose the correct graph below. O A. O C. O B. C Q 18 1 The cutoff values are degrees. (Use a comma to separate answers as needed. Round to two decimal places as needed.) O D.
Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. Assume 2.7% of the thermometers are rejected because they have readings that are too high and another 2.7% are rejected because they have readings that are too low. Draw a sketch and find the two readings that are cutoff values separating the rejected thermometers from the others. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents the region in which thermometers are rejected? Choose the correct graph below. O A. В. D.
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P29, the 29-percentile. This is the temperature reading separating the bottom 29% from the top 71%.P29 = °C(Round answer to three decimal places)
Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. Assume 2.5% of the thermometers are rejected because they have readings that are too high and another 2.5% are rejected because they have readings that are too low. Draw a sketch and find the two readings that are cutoff values separating the rejected thermometers from the others. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents the region in which thermometers are rejected? Choose the correct graph below. O A. O B. C. OD.
c. Identify the mean and standard deviation of x. Choose the correct answer below. O A. µ and О В. н аnd o C. and O D. and o 이들
Assume that the readings on the thermometers are normally idstributed with a mean of 0° and a standard deviation of 1.00°C. Find P75, the 75 percentile. This is the temperature reading separating the bottom 75 % from the top 25 %. Drovic u My Ancwers Suhmit Ansrers
please explain how to find proportions and how I know which side the tail lands on.
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P33, the 33-percentile. This is the temperature reading separating the bottom 33% from the top 67%. P33 = %3D
Please see attached.