1. Fuel cells have been proposed for use in cars and for power generation as part of a hydrogen economy. They offer the advantages of higher efficiency and cleaner fuel with insignificant pollutants. The balanced reaction is: 2 H₂ + O₂ => 2 H₂O Hydrogen flows into a fuel cell operating at steady state at a rate of 42 lbmol/min. Air enters the fuel cell in a separate stream, at a flow rate that ensures that the oxygen is fed at 50% excess. 90% of the hydrogen entering the reactor gets reacted. Assume that all reactants and products are gaseous phase. All the left over reactants and created products leave the fuel cell in a single stream. Calculate the mole fraction of oxygen in the outlet stream.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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### Fuel Cells in Hydrogen Economy

Fuel cells have been proposed for use in cars and for power generation as part of a hydrogen economy. They offer the advantages of higher efficiency and cleaner fuel with insignificant pollutants. 

#### Reaction:
The balanced chemical reaction for the fuel cell is:
\[ 2 H_2 + O_2 \rightarrow 2 H_2O \]

Hydrogen flows into a fuel cell operating at a steady state at a rate of 42 lbmol/min. Air enters the fuel cell in a separate stream, at a flow rate that ensures that the oxygen is fed at 50% excess. 90% of the hydrogen entering the reactor gets reacted. Assume that all reactants and products are in gaseous phase. All the leftover reactants and created products leave the fuel cell in a single stream. Calculate the mole fraction of oxygen in the outlet stream.

#### Step-by-Step Explanation:

1. **Hydrogen Input:**
   - Hydrogen flow rate: 42 lbmol/min

2. **Oxygen Requirement:**
   - From the balanced reaction, 2 moles of \( H_2 \) require 1 mole of \( O_2 \). 
   - Moles of \( O_2 \) required for 42 lbmol/min of \( H_2 \):
     \[\frac{42 \text{ lbmol/min}}{2} = 21 \text{ lbmol/min} \]
   - With 50% excess oxygen, the oxygen feed rate:
     \[ 21 \text{ lbmol/min} \times 1.5 = 31.5 \text{ lbmol/min} \]

3. **Hydrogen Reaction:**
   - 90% of 42 lbmol/min of \( H_2 \) react:
     \[ 0.9 \times 42 \text{ lbmol/min} = 37.8 \text{ lbmol/min} \]
   - Leaving 10% unreacted \( H_2 \):
     \[ 0.1 \times 42 \text{ lbmol/min} = 4.2 \text{ lbmol/min} \]

4. **Oxygen Consumption:**
   - Corresponding \( O_2 \) consumed for reacted \( H_2 \):
     \[\frac{37.8 \text{ lbmol/min}}{2} = 18.9 \text{
Transcribed Image Text:### Fuel Cells in Hydrogen Economy Fuel cells have been proposed for use in cars and for power generation as part of a hydrogen economy. They offer the advantages of higher efficiency and cleaner fuel with insignificant pollutants. #### Reaction: The balanced chemical reaction for the fuel cell is: \[ 2 H_2 + O_2 \rightarrow 2 H_2O \] Hydrogen flows into a fuel cell operating at a steady state at a rate of 42 lbmol/min. Air enters the fuel cell in a separate stream, at a flow rate that ensures that the oxygen is fed at 50% excess. 90% of the hydrogen entering the reactor gets reacted. Assume that all reactants and products are in gaseous phase. All the leftover reactants and created products leave the fuel cell in a single stream. Calculate the mole fraction of oxygen in the outlet stream. #### Step-by-Step Explanation: 1. **Hydrogen Input:** - Hydrogen flow rate: 42 lbmol/min 2. **Oxygen Requirement:** - From the balanced reaction, 2 moles of \( H_2 \) require 1 mole of \( O_2 \). - Moles of \( O_2 \) required for 42 lbmol/min of \( H_2 \): \[\frac{42 \text{ lbmol/min}}{2} = 21 \text{ lbmol/min} \] - With 50% excess oxygen, the oxygen feed rate: \[ 21 \text{ lbmol/min} \times 1.5 = 31.5 \text{ lbmol/min} \] 3. **Hydrogen Reaction:** - 90% of 42 lbmol/min of \( H_2 \) react: \[ 0.9 \times 42 \text{ lbmol/min} = 37.8 \text{ lbmol/min} \] - Leaving 10% unreacted \( H_2 \): \[ 0.1 \times 42 \text{ lbmol/min} = 4.2 \text{ lbmol/min} \] 4. **Oxygen Consumption:** - Corresponding \( O_2 \) consumed for reacted \( H_2 \): \[\frac{37.8 \text{ lbmol/min}}{2} = 18.9 \text{
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