1. (Crest Vertical Curve) A vertical curve is designed for 55 mi/h and has an initial grade of +2.5% and a final grade of -1.0%. The PVT is at station 114 + 25. It is known that a point on the curve at station 112 + 75 is at elevation 240 ft. What is the stationing and elevation of the PVC? What is the stationing and elevation of the high point on the curve?

1. (Crest Vertical Curve) A vertical curve is designed for 55 mi/h and has an initial grade of +2.5% and a final grade of -1.0%. The PVT is at station 114 + 25. It is known that a point on the curve at station 112 + 75 is at elevation 240 ft. What is the stationing and elevation of the PVC? What is the stationing and elevation of the high point on the curve?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: An old equal-tangent crest vertical curve was designed with a PVI at station 117+45 and elevation of…

A: An equal tangent crest vertical curve is as below The point PVC is called as the initial tangent…

Q: 1. Consider a vertical curve with a +3/2% initial grade and -1.1% final grade. The point of…

Q: answer question 18 only

Q: the AASHTO method (“K” factors) (1/8 pts.) The station of the PVC/BVC (1/8 pts.) The station of the…

Q: A parabolic vertical curve with a grade in of 2.1%, a grade out of - 3.2%, a curve length of…

A: (Note: Since part C is asked to solve, the solution for the c part is given below.) Given: Grade in,…

Q: 19. What is the stationing (ft) of the EVC?

A: Length of curve, L = 1100ft ⇒ 11 stations. Stationing of BVC = 12+15 ft.

Q: A 1.5% grade passing at station 46+20.00 at an elevation of 369.93 ft meets a -2.5% grade passing at…

Q: have designed a vertical crest curve which joins a +3% E mph and you have determined the curve to be…

Q: 2300 ft equal tangent crest vertical curve is currently designed for 60 mph.this curve connects an…

Q: 200+00 and elevation 150.00m above the sea level. The centerline of the roadway must clear a pip…

A: According to given data A vertical curve joins a -0.5% grade to a +1.0% grade. The VPI of the…

Q: 3.3 Vertical Alignment 53 ELEMENTS OF VERTICAL CURVE DESIGN An equal-tangent vertical curve is to be…

A: I have tried to solve this problem and also write the given data in diagram plz have gone through it

Q: You have designed a vertical crest curve which joins a +3% grade and a -4% grade. The design speed…

Q: What is the length in stations for a symmetrical vertical curve with an entering grade of +5% which…

Q: 600-ft crest vertical curve is to be developed from a +1.80% grade intersecting with a -3.4% grade…

A: Given Initial grade = 1.8% Final grade = -3.4% Station PVI= 15+50= 1550ft Elevation of PVI= 315.76ft…

Q: 5. A vertical sag curve consists of an initial grade of -3.5% with a final grade of +0.5%. The…

A: Given:- An initial grade of the sag curve = -3.5% A final grade of the sag curve = +0.5% The…

Q: Determine the elevation of the middle point of the curve.

Q: a crest vertival curve connects a +4.44% grade and a -6.87% grade. The PVI is at station 43 + 15.25…

A: Hi there!! since you have posted a question with multiple subparts, we will solve the first three…

Q: An equal tangent vertical curve is intended to connect grades of 3.1% and -0.8%. If this curve is to…

Q: A 600 ft equal tangent vertical The initial grade is -3.5% and the final grade is +0.5%. Determine…

A: L=600ft

Q: you have determined the curve to be 1100 ft long. Now, you need to when the BVC is located at…

Q: An equal-tangent vertical curve connects an initial grade of -4% and a final grade of +1% and is…

A: The objective of the problem is to determine the station and elevation of the lowest point on an…

Q: You are designing a vertical sag curve joining a -3% grade to a +2% grade. The design speed is 60…

A: Given: g1=-3%g2=+2% Design speedV=60 mph.

Q: Step by step solutionProblem 1. An existing equal-tangent sag vertical curve is designed for 60 mph.…

A: Step 1:Step 2: Step 3: Step 4:

Concept explainers

Drainage of Pavements

Pavement Drainage holds ample significance, as it prevents the accumulation of water or any liquid on the surface of pavements and ensures proper drainage system. With proper design and gradual slopes provided, the water gets easily removed from the surface into the drains, which are essential during heavy rains and unusual weather conditions keeping it less prone to accidents and increasing the durability of the pavement structure.

Question

1. (Crest Vertical Curve) A vertical curve is designed for 55 mi/h and has an initial
grade of +2.5% and a final grade of -1.0%. The PVT is at station 114 + 25. It is
known that a point on the curve at station 112 + 75 is at elevation 240 ft. What is
the stationing and elevation of the PVC? What is the stationing and elevation of
the high point on the curve?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

answer question 22 only
I need the answer as soon as possible
1) An equal-tangent crest vertical curve has a 50 mi/h design speed. The initial grade is +3%. The high point is at station 33+37.43 and the PVT is at station 37+18.26. What is the elevation difference between the high point and the PVT? 2) A 1400-ft-long sag vertical curve (equal tangent) has a PVC at stateion 115+00 and elevation 750ft. The intial grade is -3.5% and the final grade is +6.5%. Determine the elevation and stationing of the low point, PVI, and PVT. If you could show as many steps taken as possible that would be helpful in me actually understanding how to do the problem. Thanks
answer question 17 only
3.9 An equal-tangent crest curve connects a +2% initial grade with a -1% final grade, and is designed for 55 mi/h. The station of the PVI is 233 + 40 with elevation 1203 ft. What is the elevation of the curve at station 234 +00?
3.7 An equal-tangent crest vertical curve is designed for 65 mi/h. The initial grade is +3.4% and the final grade is negative. What is the elevation difference between the PVC and the high point of the curve?
answer question 21 only