1. Cl₂, H₂O 2. NaOH Another mechanism for the formation of epoxides is through the formation of a chlorohydrin. Alkenes react with chlorine in the presence of H₂O to give a chlorohydrin via a cyclic chloronium ion intermediate. When the chlorohydrin is treated with strong base, HCI is eliminated and the epoxide is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions 27 →XT H H₂0 lla
1. Cl₂, H₂O 2. NaOH Another mechanism for the formation of epoxides is through the formation of a chlorohydrin. Alkenes react with chlorine in the presence of H₂O to give a chlorohydrin via a cyclic chloronium ion intermediate. When the chlorohydrin is treated with strong base, HCI is eliminated and the epoxide is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions 27 →XT H H₂0 lla
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Another mechanism for the formation of epoxides is through the formation of a chlorohydrin. Alkenes react with chlorine in the presence of H₂O to give a chlorohydrin via a cyclic chloronium ion
intermediate. When the chlorohydrin is treated with strong base, HCI is eliminated and the epoxide is formed.
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Arrow-pushing Instructions
~A
1. Cl₂, H₂O
2. NaOH
Ci:
XII
OH
O H₂O :CI:
lla](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fedbc337d-f7ce-40af-8578-7a8d9aa70a74%2Fdc75cad4-3c3f-4211-839f-ff19f33fb886%2Fsy2g2g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Another mechanism for the formation of epoxides is through the formation of a chlorohydrin. Alkenes react with chlorine in the presence of H₂O to give a chlorohydrin via a cyclic chloronium ion
intermediate. When the chlorohydrin is treated with strong base, HCI is eliminated and the epoxide is formed.
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Arrow-pushing Instructions
~A
1. Cl₂, H₂O
2. NaOH
Ci:
XII
OH
O H₂O :CI:
lla
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