Predict the direction of equilibrium in the following reaction. Explain your answer. O NH₂ + NH3

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Predict the direction of equilibrium in the following reaction. Explain your answer.**

**Reaction:**

- **Reactants:** 
  - Compound with two carbonyl groups (indicated by two double-bonded oxygen atoms to adjacent carbon atoms)
  - An anionic amine group (\(NH_2^-\))

- **Products:**
  - Resonance-stabilized enolate ion (indicated by a carbonyl group and an additional negative charge)
  - Ammonia (\(NH_3\))

**Explanation:**

In this reaction, the equilibrium direction can be predicted based on the relative acidity of the reactants and products. The equilibrium will generally favor the formation of the weaker acid and stronger base pair. 

- The doubly carbonyl-containing compound is relatively acidic due to its resonance stabilization capabilities when deprotonated, forming an enolate.
- The \(\text{NH}_2^-\) is a strong base, while \(\text{NH}_3\) is a relatively weak acid.

The reaction will thus likely favor the products side, as the enolate ion is resonance-stabilized and \(\text{NH}_3\) is a weaker acid compared to the starting carbonyl compound, making this equilibrium shift to the right.
Transcribed Image Text:**Predict the direction of equilibrium in the following reaction. Explain your answer.** **Reaction:** - **Reactants:** - Compound with two carbonyl groups (indicated by two double-bonded oxygen atoms to adjacent carbon atoms) - An anionic amine group (\(NH_2^-\)) - **Products:** - Resonance-stabilized enolate ion (indicated by a carbonyl group and an additional negative charge) - Ammonia (\(NH_3\)) **Explanation:** In this reaction, the equilibrium direction can be predicted based on the relative acidity of the reactants and products. The equilibrium will generally favor the formation of the weaker acid and stronger base pair. - The doubly carbonyl-containing compound is relatively acidic due to its resonance stabilization capabilities when deprotonated, forming an enolate. - The \(\text{NH}_2^-\) is a strong base, while \(\text{NH}_3\) is a relatively weak acid. The reaction will thus likely favor the products side, as the enolate ion is resonance-stabilized and \(\text{NH}_3\) is a weaker acid compared to the starting carbonyl compound, making this equilibrium shift to the right.
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