Please solve ASAP ### Problem 1: Structure and Reaction of N-α-acetyl-lysine**1. Below is the structure of N-α-acetyl-lysine.**![N-alpha-acetyl-lysine structure](image-link-placeholder)**Structure:**- The structure depicted is N-alpha-acetyl-lysine. It consists of a lysine backbone with an acetyl group attached to the alpha-nitrogen.**Tasks:****a. Label the chiral center(s) in the N-α-acetyl-lysine with *.**- Identify the carbon atom in the molecule that has four different groups attached to it, which makes it a chiral center, and label it with an asterisk (*).**b. Draw the molecule in its most common protonation state at pH 7.**- At pH 7, identify the protonation state of N-alpha-acetyl-lysine, considering the ionizable groups typically found in amino acids and their derivatives (e.g., amino, carboxyl, and side chain groups).**c. The molecule can be made from the reaction of lysine with acetyl chloride (see structures above). Draw the reaction mechanism, including any relevant intermediate, using the arrow formalism.****Structures:**- Lysine: Contains an amino group, a carboxyl group, and a side chain.- Acetyl chloride: Contains an acetyl group connected to chlorine.- Illustrate the step-by-step reaction pathway, using arrows to show the movement of electrons during the formation of N-alpha-acetyl-lysine from lysine and acetyl chloride.**d. What's the name of the new functional group that is formed in (c)?**- Identify the new functional group produced during the reaction between lysine and acetyl chloride (e.g., amide bond).**e. Imagine that you carry out the reaction under the following conditions: neutral pH, acetonitrile, 10 mM lysine, 10 mM acetyl chloride. The reaction will yield one other (i.e., additional) major organic product. Draw this organic product.**- Consider possible additional reactions or side products that can form under these conditions, and draw the structure of the major product.**f. Now imagine that you carry out the reaction under the following conditions: neutral pH, acetonitrile, 10 mM lysine

1. Below is the structure of N-a-acetyl-lysine. LHO H2N 'N' H unotos TEE MHD N-alpha-acetyl-lysine Label the chiral center(s) in the N-a-acetyl-lysine with *. b. Draw the molecule in its most common protonation state at pH 7. a. HO H2N NH2 TCI lysine acetyl chloride C. The molecule can be made from reaction of lysine with acetyl chloride (see structures above). Draw the reaction mechanism, including any relevant intermediate, using the arrow formalism.

1. Below is the structure of N-a-acetyl-lysine. LHO H2N 'N' H unotos TEE MHD N-alpha-acetyl-lysine Label the chiral center(s) in the N-a-acetyl-lysine with *. b. Draw the molecule in its most common protonation state at pH 7. a. HO H2N NH2 TCI lysine acetyl chloride C. The molecule can be made from reaction of lysine with acetyl chloride (see structures above). Draw the reaction mechanism, including any relevant intermediate, using the arrow formalism.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Ionic interaction can be a mechanism of separation in SEC O HILIC NPLC OIEX
Cengage Learnir × | Cengage Learnir x | Cengage Learnir X OWLv2 | Online X × Ar Ex3 CH 14 and 15 prod03-cnow-owl.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?lo Question 1 1pt This question has multiple parts. Work all the parts to get the most points. Question 2 1pt Question 3 Question 4 2 pts 2 pts Data in the table were collected at 540 K for the following reaction: Question 5 1 pt CO(g) + NO2(g) → CO2 (g) + NO(g) Initial concentration (mol/L) Initial rate Question 6 Question 7 2 pts 1pt [CO] [NO2] (mol/L. h) 5.1 × 10-4 Question 8 Question 9 2 pts 1pt Question 102 pts Question 111pt 0.35 x 10 4 3.9 × 10-8 5.1 x 10-4 0.70 × 10-4 7.9 x 10-8 5.1 × 10-4 0.18 × 10-4 2.0 × 10-8 1.0 × 10-³ 0.35 × 10-4 7.7 × 10-8 Question 12 1 pt 1.5 x 10-3 0.35 × 10-4 1.2 × 10-7 Question 13 1 pt Question 14 1pt Question 151 pt a Determine the reaction order with respect to each reactant. Order with respect to CO: 1 ✓ ✓ 4 Order with respect to NO2: 1 V✓ Progress: 13/15 items Due Mar 28 at…
a. What is reactant selectivity in zeolite catalysis?
1. An enzyme-catalyzed reaction has a KM of 1 mM and a Vmax of 5 nM s-1. What is the reaction velocity when the substrate concentration is 0.25 mM? 2. If an enzyme-catalyzed reaction has a velocity of 2 mm/min and a Vmax of 10 mm/min when the substrate concentration is 0.5 mM, what is the KM?
Thank you I did not connect ln 2 to 0.693 in the first order kinetic equation.
a) Provide a mechanism for the following reactions. Be complete in your answer accounting for all product(s) and pay attention to stereochemistry where applicable. b)Show the mechanism for the steps of the following reaction and how they give the final product. Note: There is only one step in this reaction
Determine the values of KM and Vmax. For the Vmax obtained, calculate the turnover number assuming that 1 X 10-4 mol of enzyme were used. Substrate concentration (mol L-1) Velocity (mM min-1) 2.500 0.588 1.000 0.500 0.714 0.417 0.526 0.370 0.250 0.256
Please send me the question in 20 minutes it's very urgent plz
Only typed solution
Write and discuss the mechanism of the reaction that happens at the active site of the enzyme cathecol oxidase.
Now let us look at a real amino acid, alanine. Fill in the chart below for each ionizable group. You need only the relationship discussed in the pdf posted and the numbers posted below. The next 6 questions will ask for the numbers you calculated for each of the letters below. pH when Average charge of group Group Ka pKa [A]/[HA] = 1 when pH = pK alpha-COOH ~10-2 A C alpha-NH3* ~10-9 В
S $24 CHEM 107-02 Exam 1: Ju x → A ALEKS - Julianna Graham - L x + www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-lgNslkr7j8P3jH-IQUHIQg6bJxmeSyVpHOEB1plef9xyC5Ca9QlyULO-QdKyW_57MDR1Qpi-ijkNcyRp81fjPxufK3ckTA8G12 Td... O Acids and Bases Calculating the pH of a strong acid solution 0/3 Julianna A chemist dissolves 855. mg of pure perchloric acid in enough water to make up 250. mL of solution. Calculate the pH of the solution. Round your answer to 3 significant decimal places. 0 Explanation Check G MacBook Air olo 2024 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility