1. At the bottom of the Lean Clay layer described below, find the total and effective horizontal stresses, Ơh, o’h. Make necessary assumption(s) for assigning the ko values. Sand with Silt (SP-SM) Vt = 19 kN/m3 9 m Lean Clay (CL) PI = 10 Ye = 18.5 kN/m³ o', = 300 kPa m = 0.38 %3D 16 m Dense Silty Sand (SM) Ve = 20.5 kN/m3 Bedrock

Q: A normally consolidated clay is consolidated under a triaxial chamber confining pressure of σ = o'₁…

A: Detailed solution is provided belowPlease read carefullyThank you. Explanation:Step 1:Step 2:Step 3:…

Q: A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are…

A: The result of the consolidated tri-axial test are:-Confining stress Deviator stress To determine:-i)…

Q: Consolidation of Clay: Given Exercise Figure 7.4 and the accompanying information, what is the…

A: Given, Depth of clay layer, H= 6ft Porosity of clay,n=0.629Compression index, Cc=0.82Load acting at…

Q: B) For the soil profile shown in Fig. (2), determine 1- The effective and total stress at point A.…

A:

Q: Example 22 se For a normally consolidated clay (c' = 0) these are the results for a consolidated…

A: Deviator stress = sigma1 - Sigma3 Chamber pressure = Sigma3

Q: The effective internal friction angle of a normal compacted clay is 33°, the triaxial test of this…

A: Given a clay specimen in which triaxial test is performed, it required to calculate water pressure…

Q: 7. Figure 6 shows a clay layer of thickness 2H = 8m contained between two sand layers and subjected…

A:

Q: A saturated clay layer (300cm in thickness) was sitting upon the rock, its unit weight was y= 20…

A: Given values: Saturated clay layer thickness=300cm unit weight of soil=20kN/m3 Cc=0.2 Cr=0.04…

Q: 7. A specimen of soil was collected from a depth of 10 m in a deposit of clay. The ground water…

A:

Q: The stresses on a failure plane in a drained triaxial test on sand are as Follows: Normal Stress nf…

A:

Q: The water table in a deposit of uniform sand is located at 2 m below the ground level. Assuming the…

A: The water table in a deposit of uniform sand is located at 2 m below the ground level. The soil…

Q: 2.11 From the soil profile shown in Figure P2.11, determine the total stress, pore water pressure,…

A:

Q: The results of a consolidated undrained test, in which o3 = 392 kN/m², on a normally consolidated…

A: Given : Results of a consolidated undrained test on a normally consolidated clay                σ3 =…

Q: =) For the soil deposit shown below, determine the maghltu following total stress pore water…

A: Total stress :⇒at z=0σ=0⇒at z=4σ=1.924=7.68tm3⇒at z=11σ=1.924+2.111-4=22.38tm3

Q: For a normally consolidated insensitive clay 0_CD= 30°. Deviator stress at failure of the same soil…

A:

Q: effective stress (kPa) at the base of each soil layer listed below. Assume the water table rest 4 m…

A: The given data is shown in the diagram as below.To determine the total stress, pore water pressure…

Q: Using the expression above, determine the distribution of the total and effective vertical stress…

A: From the given data we will calculate the total vertical stress and effective stress at each transit…

Calculation of Settlement

The vertical displacement of the structural foundation due to the loading from the superstructure is known as settlement. It is due to the reduction of air voids present in the soil. The amount of vertical displacement depends on the bearing capacity of the soil on which the foundation is laid. The effect of the settlement depends on the magnitude of settlement, uniformity, and the structural design of the structure. The maximum allowable settlement for residential and office buildings should be less than 18 mm, for industrial buildings, it is 38 mm and for commercial buildings, it is 25 mm.