A normally consolidated clay is consolidated under a triaxial chamber confiningpressure of σ = o'₁ = 495kN/m² and '= 29° (again for normally consolidated soil assumec' = 0). Calculate the axial stress and radial stress at failure for the following cases and draw thestress path in p'-q planea. By increasing the axial stress and reducing the radial stress such that 20%, +0% = const.b. By reducing the axial stress and increasing the radial stress such that 2σ +σ = const .

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Answered: A normally consolidated clay is…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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indicate the final answer in 3 decimal places.
A consolidated undrained triaxial compression test is conducted on a normally consolidated clay at a confining pressure of 75 kPa. The deviator stress at failure is 60 kPa and the pore-water pressure measured at failure is 35 kPa. The effective angle at internal friction of the soil will be
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A consolidated undrained (CU) triaxial compression test is conducted on a normally consolidated clay at a confining pressure of 100 kPa. The deviator stress at failure is 80 kPa, and the pore-water pressure measured at failure is 50 KPa. The effective angle of internal friction (indegrees, up to one decimal place) of the soil is..?
A sample of normally consolidated clay was subjected to a consolidated undrained triaxial compression test that was carried out until the specimen failed at a deviator stress of 50 kN/m2. The pore water pressure at failure was recorded to be 20 kN/m2 and confining pressure of 50 kN/m2 was used in the test. Determine the consolidated undrained friction angle.
A NC clay soil has the total stress friction angle (φ) = 10⁰. When the soil is conducting SCU triaxial test, if the confining stress (σ3) is 200kPa and the Slemption A parameter is 0.60, what are the deviatoric stress (Δσd) at failure? the excess pore water pressure at failure (udf)? and the effective stress friction angle (φ’)?
A clayey sand has a friction angle of 30 degrees and a cohesion of 200 psf. In the ground, the sand has a principle horizontal Normal Stress of 1000 psf acting on it. a)Determine the principle vertical normal stress necessary to cause faliure of the sand. Assume no shear stresses on the element and that the vertical stress is the major principle axis. b) Determine the shear stress and normal stress on the plane experiencing faliure c)What is the inclination of the faliure plane with respect to the horizontal
A consolidated-drained triaxial test was conducted on a normally consolidated clay. The results kN o', = 276 kN (A0,), = 276 m² are as follows: Determine: (a) The angle of friction o; (b) The angle 0 that the failure plane makes with the major principal plane, and (c) The normal stress o’ and shear stress t, on the failure plane.
A sample of soil (0.1 m X 0.1 m) is subjected to the forces shown in Figure below. Determine (a) σ1, σ3, and α;(b) the maximum shear stress; and (c) the stresses on a plane oriented at 30° counterclockwise from the major principal stress plane.
Q: A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as following: confining stress, G3 = 150 kN/m² and deviator stress, (Aod)t = 150 kN/m². i) Determine angle of friction, q; ii) Determine angle 0 that the failure plane makes with the major principal plane; iii) Find the normal stress and the shear stress ty on the failure plane; and iv) Determine the effective normal stress on the plane of maximum shear stress. Express your results in two decimal places.
Tri-Axial Tests
1. Given the figure below plot the pore pressure, total stress and effective stress at the top, bottom and midpoint of each soil layer, provide a plot with all umerical values of depth and stress in tabular form and on a depth v stress plot. Oft Sand Vmoist = 122 pcf Ysat = 151 pcf I 12ft 30ft Clay Ysat = 144 pcf %3D 70ft Sand Ysat = 128 pcf 120ft

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