1. Answer the following questions for the titration of an aqueous solution of oxalic acid by an aqueous solution of potassium hydroxide. a. If 1 mole of oxalic acid (H₂C204) is combined with 1 mole KOH, write a balanced net ionic equation for the reaction that occurs. b. If 1 mole of KOH is added to the products of the reaction above, write a balanced net ionic equation for what occurs. C. Add the two equations in part a and b to get an overall balanced net ionic for the reaction of oxalic acid and KOH. d. An aqueous solution of oxalic acid is titrated with 0.102 M KOH. If 33.45 mL of KOH is required to reach the second equivalence point, how many moles of the oxalic acid solution were in the original solution?

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1. Answer the following questions for the titration of an aqueous solution of oxalic acid by an aqueous
solution of potassium hydroxide.
a. If 1 mole of oxalic acid (H₂C₂O4) is combined with 1 mole KOH, write a balanced net ionic
equation for the reaction that occurs.
b. If 1 mole of KOH is added to the products of the reaction above, write a balanced net ionic
equation for what occurs.
c. Add the two equations in part a and b to get an overall balanced net ionic for the reaction of
oxalic acid and KOH.
d. An aqueous solution of oxalic acid is titrated with 0.102 M KOH. If 33.45 mL of KOH is required
to reach the second equivalence point, how many moles of the oxalic acid solution were in the
original solution?
Transcribed Image Text:1. Answer the following questions for the titration of an aqueous solution of oxalic acid by an aqueous solution of potassium hydroxide. a. If 1 mole of oxalic acid (H₂C₂O4) is combined with 1 mole KOH, write a balanced net ionic equation for the reaction that occurs. b. If 1 mole of KOH is added to the products of the reaction above, write a balanced net ionic equation for what occurs. c. Add the two equations in part a and b to get an overall balanced net ionic for the reaction of oxalic acid and KOH. d. An aqueous solution of oxalic acid is titrated with 0.102 M KOH. If 33.45 mL of KOH is required to reach the second equivalence point, how many moles of the oxalic acid solution were in the original solution?
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Here we have to write the balanced net ionic equation for the reaction of KOH with H2C2O4 at first equivalent point and at second equivalent point.

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