A student titrated a 15.00-mL sample of an unknown monoprotic acid (HA) with a 0.136 M solution of NaOH. It took 23.47 mL of the base to reach the equivalence point. a. How many moles of NaOH were required to reach the equivalence point? b. How many moles of acid were in the sample? c. What is the concentration of the original acid sample?

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moles of NaOH
moles
moles of acid
moles
Concentration of acid in original sample
in M
Volume
in mL
Transcribed Image Text:moles of NaOH moles moles of acid moles Concentration of acid in original sample in M Volume in mL
A student titrated a 15.00-mL sample of an unknown monoprotic acid (HA) with a 0.136 M solution of NaOH. It took 23.47 mL of the base to reach the equivalence
point.
a. How many moles of NaOH were required to reach the equivalence point?
b. How many moles of acid were in the sample?
c. What is the concentration of the original acid sample?
d. At what volume of base added should a student look at their data to determine the value of pKa for their acid?
Transcribed Image Text:A student titrated a 15.00-mL sample of an unknown monoprotic acid (HA) with a 0.136 M solution of NaOH. It took 23.47 mL of the base to reach the equivalence point. a. How many moles of NaOH were required to reach the equivalence point? b. How many moles of acid were in the sample? c. What is the concentration of the original acid sample? d. At what volume of base added should a student look at their data to determine the value of pKa for their acid?
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