1. A stone of mass 3 kg sits on a planet's surface. If an alien pushes on the stone with a downward force of 100 N, what is the normal force magnitude, n, on the stone? The gravitation acceleration on the surface of the planet, gplanet = 5 m/s2. A. 70 N B. 115 N C. 15 N D. 150 N E. 18 N

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1. A stone of mass 3 kg sits on a planet's surface. If an alien pushes on the stone with a
downward force of 100 N, what is the normal force magnitude, n, on the stone? The gravitation
acceleration on the surface of the planet, gplanet = 5 m/s2.
A. 70 N
B. 115 N
A. +2 m/s²
B. +1 m/s2
C. 15 N
2. A person weighs a fish of mass m = 10 kg on a spring scale attached to the ceiling of an
elevator as the elevator is coming to a stop. The measured weight of the fish is 80 N. What was
the vertical acceleration of the elevator before it stops over 5.0 s? Use g = 10 m/s².
a m
C. -1 m/s2
A. T-m1g=m₁a; m2gsin + T = m2a
C. T-m1g = m₁a;
T-m2gsin = m2a
E. T-m₁g=m₁a; m2gsin - T = m₂a
0
D. 150 N
m₂
D. -3 m/s²
3. A ball of mass m₁ and a block of mass m2 are attached by a lightweight cord that passes
over frictionless pulley of negligible mass as shown in the figure below. The block m2 lies on a
frictionless incline of angle and is accelerated downward with a magnitude a. With T is the
tension in the cord and g is the gravitational acceleration, the correct Newton's second law
statements of the ball and the block are:
E. 18 N
B. m1g - T = m₁a;
D. m₁g - T = m₁a;
E. -2 m/s2
T-m2gcos
m2gcos
-
= m2a
T=
= m2a
Transcribed Image Text:1. A stone of mass 3 kg sits on a planet's surface. If an alien pushes on the stone with a downward force of 100 N, what is the normal force magnitude, n, on the stone? The gravitation acceleration on the surface of the planet, gplanet = 5 m/s2. A. 70 N B. 115 N A. +2 m/s² B. +1 m/s2 C. 15 N 2. A person weighs a fish of mass m = 10 kg on a spring scale attached to the ceiling of an elevator as the elevator is coming to a stop. The measured weight of the fish is 80 N. What was the vertical acceleration of the elevator before it stops over 5.0 s? Use g = 10 m/s². a m C. -1 m/s2 A. T-m1g=m₁a; m2gsin + T = m2a C. T-m1g = m₁a; T-m2gsin = m2a E. T-m₁g=m₁a; m2gsin - T = m₂a 0 D. 150 N m₂ D. -3 m/s² 3. A ball of mass m₁ and a block of mass m2 are attached by a lightweight cord that passes over frictionless pulley of negligible mass as shown in the figure below. The block m2 lies on a frictionless incline of angle and is accelerated downward with a magnitude a. With T is the tension in the cord and g is the gravitational acceleration, the correct Newton's second law statements of the ball and the block are: E. 18 N B. m1g - T = m₁a; D. m₁g - T = m₁a; E. -2 m/s2 T-m2gcos m2gcos - = m2a T= = m2a
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