Hello, can you help me solve this problem? I need to know the formula and complete and detailed solution of this to be my review on my upcoming exam. I really appreciate any help you can provide.Pretty please, Thank you in advance. A 0.275 – kg block is attached at the end of a horizontalspring (k = 125 N/m). When the block is 0.015m from its equilibriumposition, its speed is 0.57 m/s. It is observed that the block and the springare in simple harmonic motion. Determine:a. The block's total energy at any point of its motionb. The amplitude of motionc. The maximum speed during its motion

The mass of the block is given as, m=0.275 kg The spring constant of the spring is given as, k=125…

Answered: A 0.275 - kg block is attached at the…

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