A particle is trapped in a one-dimensional potential with energy eigenfunctions n (r) and corresponding energy eigenvalues En. The wave function describing the state is 3 v (2,0) = (2) +(2). Using the wave function above, an inexperienced colleague has calculated the following probabilities: P(E3) = 0.64 and P(E4)= -0.36. Is their answer
A particle is trapped in a one-dimensional potential with energy eigenfunctions n (r) and corresponding energy eigenvalues En. The wave function describing the state is 3 v (2,0) = (2) +(2). Using the wave function above, an inexperienced colleague has calculated the following probabilities: P(E3) = 0.64 and P(E4)= -0.36. Is their answer
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Transcribed Image Text:A particle is trapped in a one-dimensional potential with energy
eigenfunctions n (r) and corresponding energy eigenvalues En. The wave
function describing the state is
3
V(x,0) = 3(x) +1₁(x).
Using the wave function above, an inexperienced colleague has calculated the
following probabilities: P(E3) = 0.64 and P(E₁) = -0.36. Is their answer
Transcribed Image Text:reasonable and why? If not, can you offer an explanation of what they did
wrong, and give the correct results?
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