1. A solution containing 50% KOH is fed at a rate of 1000 mol/h to an evaporator to produce a concentrated solution containing 80%mol KOH. The concentrated solution is then fed to a crystallizer to produce a filter cake containing 90% pure KOH and 10% mother liquor (60% KOH solution). The rest of the mother liquor (60% KOH solution) is recycled back to the evaporator. Determine the values of B, C, P and W. Refer to the figure below. H,0 TW F-1000 mole/ B, 8O% KOH P, S0% pure KOH filter 50% by mole KOH 10% (s0s KOH solution) 60% KOH
1. A solution containing 50% KOH is fed at a rate of 1000 mol/h to an evaporator to produce a concentrated solution containing 80%mol KOH. The concentrated solution is then fed to a crystallizer to produce a filter cake containing 90% pure KOH and 10% mother liquor (60% KOH solution). The rest of the mother liquor (60% KOH solution) is recycled back to the evaporator. Determine the values of B, C, P and W. Refer to the figure below. H,0 TW F-1000 mole/ B, 8O% KOH P, S0% pure KOH filter 50% by mole KOH 10% (s0s KOH solution) 60% KOH
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter13: The Chemistry Of Solutes And Solutions
Section: Chapter Questions
Problem 16QRT
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![1. A solution containing 50% KOH is fed at a rate of 1000 mol/h to an evaporator to produce a
concentrated solution containing 80%mol KOH. The concentrated solution is then fed to a
crystallizer to produce a filter cake containing 90% pure KOH and 10% mother liquor (60% KOH
solution). The rest of the mother liquor (60% KOH solution) is recycled back to the evaporator.
Determine the values of B, C, P and W. Refer to the figure below.
H,0 TW
P, 9O% pure KOH filter
10% (s0% KOH solution)
F-100X0 mole/hr
B, 80% KOH
50% by mole KOH
60% KOH](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffe13b983-fee5-403f-9a8b-03fb038d35ab%2F0f80a348-fe0a-4b01-870c-becac2d1ed0d%2Fvbm5kha_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. A solution containing 50% KOH is fed at a rate of 1000 mol/h to an evaporator to produce a
concentrated solution containing 80%mol KOH. The concentrated solution is then fed to a
crystallizer to produce a filter cake containing 90% pure KOH and 10% mother liquor (60% KOH
solution). The rest of the mother liquor (60% KOH solution) is recycled back to the evaporator.
Determine the values of B, C, P and W. Refer to the figure below.
H,0 TW
P, 9O% pure KOH filter
10% (s0% KOH solution)
F-100X0 mole/hr
B, 80% KOH
50% by mole KOH
60% KOH
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