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1. A series RLC circuit with R= 15 Q, C= L d 4.72 µF and L=25.3 mH the AC power supply is providing 75 V rms at 550 Hz a) Find rms current in the circuit b) The rms a C AVab,AVpc AVcd AVpdand AVad mindful when adding two or more voltages Be these are vectors! c)The average power dissipated by each element and the circuit,

1. A series RLC circuit with R= 15 Q, C= L d 4.72 µF and L=25.3 mH the AC power supply is providing 75 V rms at 550 Hz a) Find rms current in the circuit b) The rms a C AVab,AVpc AVcd AVpdand AVad mindful when adding two or more voltages Be these are vectors! c)The average power dissipated by each element and the circuit,

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**Series RLC Circuit Analysis** **Description:** The image depicts a series RLC circuit comprised of a resistor (R), capacitor (C), and inductor (L) connected to an AC power source. The circuit components and their values are as follows: - Resistor (R) = 15 Ω - Capacitor (C) = 4.72 μF - Inductor (L) = 25.3 mH The AC power supply provides 75 V rms at 550 Hz. **Tasks:** 1. Calculate the RMS current in the circuit. 2. Determine the RMS voltages across each component: - \(ΔV_{ab}\) - \(ΔV_{bc}\) - \(ΔV_{cd}\) - \(ΔV_{bd}\) - \(ΔV_{ad}\) *Note:* Be mindful that these voltages are vectors, and must be added accordingly. 3. Compute the average power dissipated by each circuit element and the entire circuit. Specifically, compute the power for the capacitor and the inductor. **Answers:** - **Current (a):** 2.49 A - **Voltages (b):** - \(ΔV_{ab}\) = 37.4 V - \(ΔV_{bc}\) = 153 V - \(ΔV_{cd}\) = 218 V - \(ΔV_{bd}\) = 65 V - \(ΔV_{ad}\) = 75 V - **Average Power (c):** - Total average power (\(P_{res}\)) = 93 W - Capacitor power (\(P_{cap}\)) = 0 - Inductor power (\(P_{ind}\)) = 0 - Circuit power = \(P_{res} = 39\) W Consider why these values have been obtained, especially regarding power for the capacitor and inductor. Understanding the nature of power dissipation in reactive components is crucial in AC circuits analysis.
Transcribed Image Text:**Series RLC Circuit Analysis** **Description:** The image depicts a series RLC circuit comprised of a resistor (R), capacitor (C), and inductor (L) connected to an AC power source. The circuit components and their values are as follows: - Resistor (R) = 15 Ω - Capacitor (C) = 4.72 μF - Inductor (L) = 25.3 mH The AC power supply provides 75 V rms at 550 Hz. **Tasks:** 1. Calculate the RMS current in the circuit. 2. Determine the RMS voltages across each component: - \(ΔV_{ab}\) - \(ΔV_{bc}\) - \(ΔV_{cd}\) - \(ΔV_{bd}\) - \(ΔV_{ad}\) *Note:* Be mindful that these voltages are vectors, and must be added accordingly. 3. Compute the average power dissipated by each circuit element and the entire circuit. Specifically, compute the power for the capacitor and the inductor. **Answers:** - **Current (a):** 2.49 A - **Voltages (b):** - \(ΔV_{ab}\) = 37.4 V - \(ΔV_{bc}\) = 153 V - \(ΔV_{cd}\) = 218 V - \(ΔV_{bd}\) = 65 V - \(ΔV_{ad}\) = 75 V - **Average Power (c):** - Total average power (\(P_{res}\)) = 93 W - Capacitor power (\(P_{cap}\)) = 0 - Inductor power (\(P_{ind}\)) = 0 - Circuit power = \(P_{res} = 39\) W Consider why these values have been obtained, especially regarding power for the capacitor and inductor. Understanding the nature of power dissipation in reactive components is crucial in AC circuits analysis.
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