A charged particle of mass m = 57.2 g and charge q = +2.14 µC is attached to a massless string of length e = 25.5 cm and spun in circular motion with w = 7.85 rad/s. At the moment shown the charged particle is passing through an electric field of strength E = 3.91 x 105 N/C that is angled above the horizontal direction at an angle of o = 18.3°. (a) What is the angle 0 that the massless string makes with the vertical direction? E m, q can you help me with my homework Need help with the problem below
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A: m1=1.95g=0.00195Kgq1=15.0μC=15×10−6Cv1i=16m/sm2=5.25g=0.00525Kgq2=8.50μC=8.50×10−6C
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