1. A moderately sinuous trapezoidal channel will be excavated into cohesionless earth containing fine gravel having an average particle size of 0.2 inches. The particles are very angular. The bottom slope is 0.0005, and the design discharge is 135 ft³/s. Using n=0.022 and m=3.0, proportion the channel section.

Q: A circular culvert of 1.532 m diameter, flow Q = 2.32 m3 / s, depth 1 m and n = 0.014, calculate the…

A: Discharge (Q) = 2.32 m3/sDiameter of culvert (d) = 1.532 mDepth of water (y) = 1 m n = 0.014To…

Q: The weir shown below is 50 m long ● Draw a flow net for the flow under the weir Calculate the rate…

A: Given Data:The length of a weir is, The flow net for the flow under the weir:From the above figure,…

Q: yo o th y2

A:

Q: Question attached

A: Solution: Determine the dimensionless time factor Tc for the given ramp…

Q: b- Mark the following statement with True or False: 1. The protection works are now designed in…

A: This question is related to Water resources engineering from Civil Engineering.This is TRUE &…

Q: A channel designed by Lacey's theory has a velocity of 0.88 m/sec. The silt factor is 1.1. Then…

A: Given- Lacey's Theory- Velocity V=0.88 m/s, Silt factor f=1.1, To Find- The hydraulic mean depth R.

Q: A rectangular-shaped, weedy excavated channel with width b = 30 ft is laid on a slope of 8 ft/mile.…

A:

Q: b) Design a box culvert for the given data: Q = 43.8 m³/sec; length of culvert (L) = 50 m; Ke = 0.3;…

A:

Q: An earthen channel in good condition carries a discharge of 10.0 cumecs with a m velocity of 0.7…

A: Given datadischarge, Q = 10.0 cumecsVelocity, V = 0.7 m/sBottom width, B =2 x dBazin's coefficient…

Q: 3. A culvert with a headwall is to be laid through a road embankment at the natural stream slope of…

A: Given data:-  Length of the culvert, L = 100 m Natural steam slope, S = 0.004  Width, w = 1500 mm…

Q: 1.Prove the best hydraulic section for a rectangular channel.…

A: For the channel according to hydraulic requirement, we construct in the various shape such as…

Q: A wide, shallow sand-bed channel has a slope of 0.00105 (assume smooth channel banks). The average…

A: Given: Slope, Se = 0.00105 Flow rate, Q = 5380 ft3/s Area, A = 640 ft2

Q: A power-law channel section is to be excavated to accommodate 15 m³/s when flowing full. The channel…

A: Q= 15 m3/secS=.0007n=0.015y=1.5 mTo determine-Equation for best hydraulic power law channel section

Open Channel Flow

Open channel flow is a branch of fluid mechanics. It deals with the flow of fluid in an open conduit or free surface. In an open channel flow, gravity induces the flow of water whose surface is open to the air. This flow is free-falling rather than confined in rigid body conduits. The open channel flow depends upon two parameters that are the cross-section of the conduit and the velocity profile. Practical examples of open channel flow are streams, rivers, canals, and other drainage systems.In open channel flow, the cross-sectional area of at least one of the sides is exposed to air, and the surface of water faces atmospheric pressure. This flow is also known as free gravity flow. The cross-sectional area of the conduit can be either man-made or a natural channel. For instance, the flow in rivers and streams are natural conduits, and the flow in a canal and sanitary systems are man-made or engineered channels.