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1) What is (are) the product of the following reactions? H I N. O =0 Cl Pyridine 1) H3O+ OMe 2) CH3COCI, pyridine H₂O+ Heat

1) What is (are) the product of the following reactions? H I N. O =0 Cl Pyridine 1) H3O+ OMe 2) CH3COCI, pyridine H₂O+ Heat

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Title:** Reaction Product Analysis **Question:** What is (are) the product(s) of the following reactions? **Reaction 1:** - **Reactants:** N,N-diphenylamine, acetyl chloride (CH3COCl) - **Condition:** Pyridine - **Explanation:** The reaction involves acetylation of the amine using acetyl chloride. Pyridine acts as a base to facilitate the reaction, resulting in the formation of an amide. **Reaction 2:** - **Reactants:** Methyl 2,2-dimethylpropanoate - **Conditions:** - Step 1: Hydrolysis using H3O+ - Step 2: Reaction with acetyl chloride (CH3COCl), pyridine - **Explanation:** In the first step, the ester undergoes acid-catalyzed hydrolysis to form the corresponding carboxylic acid. In the second step, acetyl chloride converts the acid into its corresponding acyl chloride in the presence of pyridine. **Reaction 3:** - **Reactants:** Phthalic anhydride - **Condition:** H3O+ and heat - **Explanation:** Upon hydrolysis and heating, phthalic anhydride is converted into phthalic acid (a diacid). **Reaction 4:** - **Reactants:** 2,2-dimethylpropanoic acid - **Conditions:** - Step 1: Thionyl chloride (SOCl2) - Step 2: Excess dimethylamine ((CH3)2NH) - **Explanation:** In the first step, thionyl chloride converts the carboxylic acid into an acyl chloride. In the second step, excess dimethylamine reacts with the acyl chloride to form an amide. **Summary:** These reactions highlight the transformation of functional groups in organic compounds, focusing on acylation, hydrolysis, and amide formation processes.
Transcribed Image Text:**Title:** Reaction Product Analysis **Question:** What is (are) the product(s) of the following reactions? **Reaction 1:** - **Reactants:** N,N-diphenylamine, acetyl chloride (CH3COCl) - **Condition:** Pyridine - **Explanation:** The reaction involves acetylation of the amine using acetyl chloride. Pyridine acts as a base to facilitate the reaction, resulting in the formation of an amide. **Reaction 2:** - **Reactants:** Methyl 2,2-dimethylpropanoate - **Conditions:** - Step 1: Hydrolysis using H3O+ - Step 2: Reaction with acetyl chloride (CH3COCl), pyridine - **Explanation:** In the first step, the ester undergoes acid-catalyzed hydrolysis to form the corresponding carboxylic acid. In the second step, acetyl chloride converts the acid into its corresponding acyl chloride in the presence of pyridine. **Reaction 3:** - **Reactants:** Phthalic anhydride - **Condition:** H3O+ and heat - **Explanation:** Upon hydrolysis and heating, phthalic anhydride is converted into phthalic acid (a diacid). **Reaction 4:** - **Reactants:** 2,2-dimethylpropanoic acid - **Conditions:** - Step 1: Thionyl chloride (SOCl2) - Step 2: Excess dimethylamine ((CH3)2NH) - **Explanation:** In the first step, thionyl chloride converts the carboxylic acid into an acyl chloride. In the second step, excess dimethylamine reacts with the acyl chloride to form an amide. **Summary:** These reactions highlight the transformation of functional groups in organic compounds, focusing on acylation, hydrolysis, and amide formation processes.
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