1- • R2 · 4 ΚΩ Using Current Divider Rule (CDR) and series-parallel reduction find the current in R6. R3 8 ΚΩ R1 2 kΩ R5 3 mA 6kΩ3 R4 2 ΚΩ R6 3 ΚΩ IR6
1- • R2 · 4 ΚΩ Using Current Divider Rule (CDR) and series-parallel reduction find the current in R6. R3 8 ΚΩ R1 2 kΩ R5 3 mA 6kΩ3 R4 2 ΚΩ R6 3 ΚΩ IR6
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Transcribed Image Text:1-
R2
4 ΚΩ
R1
2 ΚΩ
Using Current Divider Rule (CDR) and series-parallel reduction find the current in R6.
R3
8 kΩ
la
R5>
3 mA 6kΩ3
R4
2 kΩ
R6
3kΩ
IR6
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