[1 + (- P] f S + (−1)²] XP 1+x² XP 1+x² dx = implifying and using the given formula for the pth root, we obtain ( TU dx COS = лр 2 2ni Res(f; i) = ni². -1 " -1 < p < 1.
[1 + (- P] f S + (−1)²] XP 1+x² XP 1+x² dx = implifying and using the given formula for the pth root, we obtain ( TU dx COS = лр 2 2ni Res(f; i) = ni². -1 " -1 < p < 1.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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I was able to get the first result in the sentence that starts "The conclusion is that....", but I do not understand how the simplification was done after that. How did they get the part that starts with "Simplifying and using the given formula..." Is there an identity for [1+(-1)p] that I need to use?
![which goes to zero as & →0. We apply the Residue Theorem and then let & →
R→ ∞o. The conclusion is that
> 0 and
[1 + (−1)²]
ܐܬ݂ܳ1]
XP
+x²
XP
dx
1 + x²
dx =
Simplifying and using the given formula for the pth root, we obtain
-1
So
<= 171 (COSTP) ²¹.
2лi Res(f; i) = niº.
-1 < p < 1.
0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F88e1e2e4-888b-4182-8c02-fd46dda7f6b1%2Fa9627abf-0ca8-4b1d-b608-493e0d68dc9e%2Fbc3ohx3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:which goes to zero as & →0. We apply the Residue Theorem and then let & →
R→ ∞o. The conclusion is that
> 0 and
[1 + (−1)²]
ܐܬ݂ܳ1]
XP
+x²
XP
dx
1 + x²
dx =
Simplifying and using the given formula for the pth root, we obtain
-1
So
<= 171 (COSTP) ²¹.
2лi Res(f; i) = niº.
-1 < p < 1.
0
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