1 ΜΩ 10.43 ΚΩ FIG. 7.95 Problem 18. 7.8 Enhancement-Type MOSFETS 20. For the network of Fig. 7.97, determine: a. Ing b. VGs and VDsq 4 c. Vp and Vs. d. VDS- 21. For the voltage-divider configuration of Fig. 7.98, determine: a. ID and VGSQ b. V and Vs. 24 V 10.39 ΚΩ -4 V FIG. 7.96 Problem 19. 1 ΜΩ VGSQ 22 V 1.2 ΚΩ + VGS (Th)=4V VGS (on) = 7 V VDSQ ID (on) = 5 mA 10.51 ΚΩ FIG. 7.97 Problem 20.
1 ΜΩ 10.43 ΚΩ FIG. 7.95 Problem 18. 7.8 Enhancement-Type MOSFETS 20. For the network of Fig. 7.97, determine: a. Ing b. VGs and VDsq 4 c. Vp and Vs. d. VDS- 21. For the voltage-divider configuration of Fig. 7.98, determine: a. ID and VGSQ b. V and Vs. 24 V 10.39 ΚΩ -4 V FIG. 7.96 Problem 19. 1 ΜΩ VGSQ 22 V 1.2 ΚΩ + VGS (Th)=4V VGS (on) = 7 V VDSQ ID (on) = 5 mA 10.51 ΚΩ FIG. 7.97 Problem 20.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Question
20 . It explains what formula is used to solve the problem step by step and why that formula is used.
Please explain in an easy to understand way
Also, I would like you to explain how to solve the problem
![1 ΜΩ
10.43 ΚΩ
FIG. 7.95
Problem 18.
7.8 Enhancement-Type MOSFETS
20. For the network of Fig. 7.97, determine:
a. Ing
b. VGs and VDsq
4
c. Vp and Vs.
d. VDS-
21. For the voltage-divider configuration of Fig. 7.98, determine:
a. ID and VGSQ
b. V and Vs.
24 V
10.39 ΚΩ
-4 V
FIG. 7.96
Problem 19.
1 ΜΩ
VGSQ
22 V
1.2 ΚΩ
+
VGS (Th)=4V
VGS (on) = 7 V
VDSQ
ID (on) = 5 mA
10.51 ΚΩ
FIG. 7.97
Problem 20.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F42357106-fb9d-4931-a827-5cfc1993b562%2F72be1470-94a9-4cdb-a37f-83a1602cf166%2Fud2l51_processed.png&w=3840&q=75)
Transcribed Image Text:1 ΜΩ
10.43 ΚΩ
FIG. 7.95
Problem 18.
7.8 Enhancement-Type MOSFETS
20. For the network of Fig. 7.97, determine:
a. Ing
b. VGs and VDsq
4
c. Vp and Vs.
d. VDS-
21. For the voltage-divider configuration of Fig. 7.98, determine:
a. ID and VGSQ
b. V and Vs.
24 V
10.39 ΚΩ
-4 V
FIG. 7.96
Problem 19.
1 ΜΩ
VGSQ
22 V
1.2 ΚΩ
+
VGS (Th)=4V
VGS (on) = 7 V
VDSQ
ID (on) = 5 mA
10.51 ΚΩ
FIG. 7.97
Problem 20.
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