Part 1. Thermistor sensitivity in a voltage divider Thermistors are temperature-sensitive resistors. In most thermistors, resistance decreases as temperature increases. They are good candidates for a bridge circuit, or at least a voltage divider. As an example, to build a -20° C freezer one might use an Ice Cube Sensor from Vishay. It is an NTC thermistor, meaning that it has a negative temperature coefficient: as temperature increases the resistance decreases. A thermistor's temperature coefficient varies according to temperature, but at any given temperature it is very reliable. The Ice Cube thermistor has a resistance of 96.4 k at -20° C, and for every Kelvin increase in temperature its resistance drops by 5.8%. Note that the function R(T) is non-linear, but we can linearize the function around -20° C by evaluating its first derivative at that temperature. 1a. Show that you could use a simple voltage divider to achieve an output of 2.0 V when the temperature is -20°. In practice, your supply voltage of +5 V would be applied across three components in series: the thermistor, a standard resistor, and a potentiometer of 10 k or less. The potentiometer is used because resistors have some manufacturing tolerance (error), and you can adjust the potentiometer to accommodate that error. Here, let's assume that you can buy the perfect resistor for your setup, and call it R2. Set up the circuit so the output voltage increases when the temperature increases. 1b. Determine the sensitivity of your circuit in volts/Kelvin.

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
Question
Part 1. Thermistor sensitivity in a voltage divider
Thermistors are temperature-sensitive resistors. In most thermistors, resistance decreases
as temperature increases. They are good candidates for a bridge circuit, or at least a
voltage divider. As an example, to build a -20° C freezer one might use an Ice Cube Sensor
from Vishay. It is an NTC thermistor, meaning that it has a negative temperature
coefficient: as temperature increases the resistance decreases. A thermistor's temperature
coefficient varies according to temperature, but at any given temperature it is very reliable.
The Ice Cube thermistor has a resistance of 96.4 k at -20° C, and for every Kelvin increase
in temperature its resistance drops by 5.8%. Note that the function R(T) is non-linear, but
we can linearize the function around -20° C by evaluating its first derivative at that
temperature.
1a. Show that you could use a simple voltage divider to achieve an output of 2.0 V when the
temperature is -20°. In practice, your supply voltage of +5 V would be applied across
three components in series: the thermistor, a standard resistor, and a potentiometer of
10 k or less. The potentiometer is used because resistors have some manufacturing
tolerance (error), and you can adjust the potentiometer to accommodate that error.
Here, let's assume that you can buy the perfect resistor for your setup, and call it R2.
Set up the circuit so the output voltage increases when the temperature increases.
1b. Determine the sensitivity of your circuit in volts/Kelvin.
Transcribed Image Text:Part 1. Thermistor sensitivity in a voltage divider Thermistors are temperature-sensitive resistors. In most thermistors, resistance decreases as temperature increases. They are good candidates for a bridge circuit, or at least a voltage divider. As an example, to build a -20° C freezer one might use an Ice Cube Sensor from Vishay. It is an NTC thermistor, meaning that it has a negative temperature coefficient: as temperature increases the resistance decreases. A thermistor's temperature coefficient varies according to temperature, but at any given temperature it is very reliable. The Ice Cube thermistor has a resistance of 96.4 k at -20° C, and for every Kelvin increase in temperature its resistance drops by 5.8%. Note that the function R(T) is non-linear, but we can linearize the function around -20° C by evaluating its first derivative at that temperature. 1a. Show that you could use a simple voltage divider to achieve an output of 2.0 V when the temperature is -20°. In practice, your supply voltage of +5 V would be applied across three components in series: the thermistor, a standard resistor, and a potentiometer of 10 k or less. The potentiometer is used because resistors have some manufacturing tolerance (error), and you can adjust the potentiometer to accommodate that error. Here, let's assume that you can buy the perfect resistor for your setup, and call it R2. Set up the circuit so the output voltage increases when the temperature increases. 1b. Determine the sensitivity of your circuit in volts/Kelvin.
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,