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1) A Warren bridge truss is shown to the below. (a) Determine the support reactions at A and K. (b) Determine the force in members CE, DE, and DF using method of joints. (c) Determine the force in members CE, DE, and DF using method of sections. (Note: A is a roller and K is a pin.) Ans: Ay 8400 lb (1), Kx = 0, K, = 3600 lb (↑), FCE = 8000 lb (T), FDE= 2600 lb (T), = 9000 lb (C). [Intermediate answers for method of joints: FAB = 9100 lb (C), FAC = 3500 lb (T), FBC = 9100 lb (T), FBD = 7000 lb (C), FcD = 2600 lb (C)] %3D %3D %3D FDF %3D %3D %3D %3D

1) A Warren bridge truss is shown to the below. (a) Determine the support reactions at A and K. (b) Determine the force in members CE, DE, and DF using method of joints. (c) Determine the force in members CE, DE, and DF using method of sections. (Note: A is a roller and K is a pin.) Ans: Ay 8400 lb (1), Kx = 0, K, = 3600 lb (↑), FCE = 8000 lb (T), FDE= 2600 lb (T), = 9000 lb (C). [Intermediate answers for method of joints: FAB = 9100 lb (C), FAC = 3500 lb (T), FBC = 9100 lb (T), FBD = 7000 lb (C), FcD = 2600 lb (C)] %3D %3D %3D FDF %3D %3D %3D %3D

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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### Analysis of a Warren Bridge Truss #### Problem Statement 1) A Warren bridge truss is shown below. - (a) Determine the support reactions at points A and K. - (b) Determine the force in members CE, DE, and DF using the method of joints. - (c) Determine the force in members CE, DE, and DF using the method of sections. (Note: A is a roller and K is a pin support.) #### Calculated Values - **Reactions at Supports:** - \( A_y = 8400 \, \text{lb (up)} \) - \( K_x = 0 \) - \( K_y = 3600 \, \text{lb (up)} \) - **Member Forces (Method of Sections):** - \( F_{CE} = 8000 \, \text{lb (T)} \) - \( F_{DE} = 2600 \, \text{lb (T)} \) - \( F_{DF} = 9000 \, \text{lb (C)} \) - **Intermediate Answers (Method of Joints):** - \( F_{AB} = 9100 \, \text{lb (C)} \) - \( F_{AC} = 3500 \, \text{lb (T)} \) - \( F_{BC} = 9100 \, \text{lb (T)} \) - \( F_{BD} = 7000 \, \text{lb (C)} \) - \( F_{CD} = 2600 \, \text{lb (C)} \) #### Diagram Description - The truss is a series of interconnected triangles forming a bridge-like structure. - It has vertical members labeled A, C, E, G, I, and K, with horizontal members bridging across (e.g., B to D, D to F, etc.). - The truss spans across a total distance of 60 feet, divided into segments of varying lengths: 6.25 ft and 12.5 ft. - Vertical loads of 6000 lb each are applied at points C and G. - Supports: - Point A has a roller support. - Point K has a pin support. - Member forces are evaluated to determine forces in tension (T) and
Transcribed Image Text:### Analysis of a Warren Bridge Truss #### Problem Statement 1) A Warren bridge truss is shown below. - (a) Determine the support reactions at points A and K. - (b) Determine the force in members CE, DE, and DF using the method of joints. - (c) Determine the force in members CE, DE, and DF using the method of sections. (Note: A is a roller and K is a pin support.) #### Calculated Values - **Reactions at Supports:** - \( A_y = 8400 \, \text{lb (up)} \) - \( K_x = 0 \) - \( K_y = 3600 \, \text{lb (up)} \) - **Member Forces (Method of Sections):** - \( F_{CE} = 8000 \, \text{lb (T)} \) - \( F_{DE} = 2600 \, \text{lb (T)} \) - \( F_{DF} = 9000 \, \text{lb (C)} \) - **Intermediate Answers (Method of Joints):** - \( F_{AB} = 9100 \, \text{lb (C)} \) - \( F_{AC} = 3500 \, \text{lb (T)} \) - \( F_{BC} = 9100 \, \text{lb (T)} \) - \( F_{BD} = 7000 \, \text{lb (C)} \) - \( F_{CD} = 2600 \, \text{lb (C)} \) #### Diagram Description - The truss is a series of interconnected triangles forming a bridge-like structure. - It has vertical members labeled A, C, E, G, I, and K, with horizontal members bridging across (e.g., B to D, D to F, etc.). - The truss spans across a total distance of 60 feet, divided into segments of varying lengths: 6.25 ft and 12.5 ft. - Vertical loads of 6000 lb each are applied at points C and G. - Supports: - Point A has a roller support. - Point K has a pin support. - Member forces are evaluated to determine forces in tension (T) and
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