1) A 40.0 mL solution of 0.0350 M piperidine (pK. = 11.13) is titrated with 0.0650 M HCI. Calculate the pH after addition of the following amounts of the HCI. /'n 40.0 ml oplossing van 0.0350 M piperidien (pka = 11.13) word getitreer met 0.0650 M HCI. Bereken die pH na byvoeging van die volgende hoeveelhede van die HCI. a) 0 mL b) 10.77 mL c) At Ve/By Ve d) 28.00 mL

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Chapter1: Chemical Foundations
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1) A 40.0 mL solution of 0.0350 M piperidine (pK. = 11.13) is titrated with 0.0650 M HCI. Calculate the pH
after addition of the following amounts of the HCI. /'n 40.0 ml oplossing van 0.0350 M piperidien (pka =
11.13) word getitreer met 0.0650 M HCI. Bereken die pH na byvoeging van die volgende hoeveelhede van die
HCI.
a) 0 mL
b) 10.77 mL
c)
d) 28.00 mL
At Ve/By Ve
e
Transcribed Image Text:1) A 40.0 mL solution of 0.0350 M piperidine (pK. = 11.13) is titrated with 0.0650 M HCI. Calculate the pH after addition of the following amounts of the HCI. /'n 40.0 ml oplossing van 0.0350 M piperidien (pka = 11.13) word getitreer met 0.0650 M HCI. Bereken die pH na byvoeging van die volgende hoeveelhede van die HCI. a) 0 mL b) 10.77 mL c) d) 28.00 mL At Ve/By Ve e
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