If you started with 0.100 M weak acid solution, how many grams of the sodium salt of the weak base must be added to create 2.50 L of pH 5.400 buffer solution?
If you started with 0.100 M weak acid solution, how many grams of the sodium salt of the weak base must be added to create 2.50 L of pH 5.400 buffer solution?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![(5) -
If you started with 0.100 M weak acid solution, how many grams of the sodium salt of
the weak base must be added to create 2.50 L of pH 5.400 buffer solution?
2.501x100 mol wa- 25 mol wa
IL
[CHN] [H₂0 = 1.42
[CsHsNH
PH=-15
[H]- 10¹.71
Ka=1.42
-71
now
(
C5H5NH (29) + H₂O(1) C5H₁N(aq) + H₂O*(aq)
.25mol
O
-X
(25-X)
XM
1.42 x 25 mol wa 3.55 mol CsHsNH
+X
XM](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5eb7def2-f89f-4660-b3ef-91d4174e8d31%2F9d9f1dee-2fe6-4f15-9dec-05c191d214c7%2Fj9c8pw7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(5) -
If you started with 0.100 M weak acid solution, how many grams of the sodium salt of
the weak base must be added to create 2.50 L of pH 5.400 buffer solution?
2.501x100 mol wa- 25 mol wa
IL
[CHN] [H₂0 = 1.42
[CsHsNH
PH=-15
[H]- 10¹.71
Ka=1.42
-71
now
(
C5H5NH (29) + H₂O(1) C5H₁N(aq) + H₂O*(aq)
.25mol
O
-X
(25-X)
XM
1.42 x 25 mol wa 3.55 mol CsHsNH
+X
XM
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