pH at this point in the titration? H₂SO4 + 2LIOH → Li₂SO4 + 2H₂O pH = [?] Hint: How many moles of H+ and OH- are present? Consider the mole ratios. pH at equivalence Enter

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### Titration Problem

**Problem Statement:**
20.0 mL of 1.0 M LiOH is added to 50.0 mL of 0.20 M H₂SO₄. What is the pH at this point in the titration?

**Chemical Reaction:**
\[ \text{H}_2\text{SO}_4 + 2\text{LiOH} \rightarrow \text{Li}_2\text{SO}_4 + 2\text{H}_2\text{O} \]

**Question:**   
\[ \text{pH} = \text{[ ? ]} \]

**Hint:**  
How many moles of H\(^+\) and OH\(^-\) are present? Consider the mole ratios.

---

### Explanation

To determine the pH of the solution after the reaction, we need to follow these steps:

1. **Calculate moles of H₂SO₄ and LiOH:**
   - Moles of H₂SO₄:
     \[ \text{Moles of H}_2\text{SO}_4 = M \times V = 0.20 \text{M} \times 50.0 \text{mL} \times \frac{1 \text{L}}{1000 \text{mL}} = 0.01 \text{moles} \]
   - Moles of LiOH:
     \[ \text{Moles of LiOH} = 1.0 \text{M} \times 20.0 \text{mL} \times \frac{1 \text{L}}{1000 \text{mL}} = 0.02 \text{moles} \]

2. **Identify the limiting reagent:**
   - Given the balanced equation, 1 mole of H₂SO₄ reacts with 2 moles of LiOH.
   - The mole ratio of H₂SO₄ to LiOH is 1:2.
   
3. **Calculate the reaction completion:**
   - 0.01 moles of H₂SO₄ would require 0.02 moles of LiOH to completely react.
   - As there are exactly 0.02 moles of LiOH, both react completely.

4. **Determine the final ionic concentrations:**
   - After reaction, none of
Transcribed Image Text:--- ### Titration Problem **Problem Statement:** 20.0 mL of 1.0 M LiOH is added to 50.0 mL of 0.20 M H₂SO₄. What is the pH at this point in the titration? **Chemical Reaction:** \[ \text{H}_2\text{SO}_4 + 2\text{LiOH} \rightarrow \text{Li}_2\text{SO}_4 + 2\text{H}_2\text{O} \] **Question:** \[ \text{pH} = \text{[ ? ]} \] **Hint:** How many moles of H\(^+\) and OH\(^-\) are present? Consider the mole ratios. --- ### Explanation To determine the pH of the solution after the reaction, we need to follow these steps: 1. **Calculate moles of H₂SO₄ and LiOH:** - Moles of H₂SO₄: \[ \text{Moles of H}_2\text{SO}_4 = M \times V = 0.20 \text{M} \times 50.0 \text{mL} \times \frac{1 \text{L}}{1000 \text{mL}} = 0.01 \text{moles} \] - Moles of LiOH: \[ \text{Moles of LiOH} = 1.0 \text{M} \times 20.0 \text{mL} \times \frac{1 \text{L}}{1000 \text{mL}} = 0.02 \text{moles} \] 2. **Identify the limiting reagent:** - Given the balanced equation, 1 mole of H₂SO₄ reacts with 2 moles of LiOH. - The mole ratio of H₂SO₄ to LiOH is 1:2. 3. **Calculate the reaction completion:** - 0.01 moles of H₂SO₄ would require 0.02 moles of LiOH to completely react. - As there are exactly 0.02 moles of LiOH, both react completely. 4. **Determine the final ionic concentrations:** - After reaction, none of
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