0.3 m P = 150 N k = 15 kN/m 0.3 m

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter7: Analysis Of Stress And Strain
Section: Chapter Questions
Problem 7.3.2P: Repeat the preceding problem using sx= 5.5 MPa. ??y= 4 MPa. and txy= 3.2 MPa.
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The scissors linkage is subjected to a force of P = 150 N as shown in the figure below. The
spring is unstretched at θ = 0◦
. All links have equal length of 0.3 m. Using the principles of virtual
work, determine the equation in terms of θ, for the system to be in equilibrium. Neglect the mass
of the links. 

 


Find the numerical value of θ, by solving the equation that you have obtained,
using a numerical method. Hint: You may look for a trial and error method, or Newton’s bisection
method, or Newton-Raphson method, etc.

 

Please solve the question

0.3 m
P = 150 N
k = 15 kN/m
0.3 m
Transcribed Image Text:0.3 m P = 150 N k = 15 kN/m 0.3 m
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