0.200 M0.00200 MTest Tube No.[FESCN2*1std (M)AbsorbanceFe(NO3)3 (mL)KSCN (mL)17.981.970.8155 (Standard)EditEditEditNG 1Info

The volume of 0.200 M Fe(NO3)3 is 17.98 mL. The volume of 0.00200 M KSCN is 1.97 mL.The reaction between Fe(NO3)3 and KSCN to form FeSCN2+ is expressed as, FeNO33+KSCN→FeSCN2+ The number of moles of Fe(NO3)3 is calculated by the formula, nFeNO33=MFeNO33×VFeNO33 Where, MFeNO33 is the molarity of Fe(NO3)3. VFeNO33 is the volume of Fe(NO3)3. Substitute the volume and molarity of Fe(NO3)3 in the above formula. nFeNO33=0.200 mol L-1×17.981000 L=3.596×10-3 molThe number of moles of KSCN is calculated by the formula, nKSCN=MKSCN×VKSCN Where, MKSCN is the molarity of KSCN. VKSCN is the volume of KSCN. Substitute the volume and molarity of KSCN in the above formula. nKSCN=0.00200 mol L-1×1.971000 L=3.94×10-6 mol The number of moles of KSCN is less than that of Fe(NO3)3. Therefore, KSCN is the limiting reactant.The number of moles of FeSCN2+ formed is equal to the number of moles of KSCN. nFeSCN2+=nKSCN=3.94×10-6 mol The total volume of the solution formed is, VT=17.98 mL+1.97 mL=19.95 mL=0.01995 L The molarity of FeSCN2+ is calculated by the formula, MFeSCN2+=nFeSCN2+VT......(1)Substitute the number of moles of FeSCN2+ and total volume of the solution in equation (1). MFeSCN2+=3.94×10-6 mol0.01995 L=1.97×10-4 MAnswer: The molarity of FeSCN2+ is 1.97×10-4 M.

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0.200 M 0.00200 M Test Tube No. [FESCN?*]std (M) Absorbance Fe(NO3)3 (mL) KSCN (mL) 17.98 1.97 0.815 5 (Standard) Edit Edit Edit NG 1 Info

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

0.200 M
0.00200 M
Test Tube No.
[FESCN2*1std (M)
Absorbance
Fe(NO3)3 (mL)
KSCN (mL)
17.98
1.97
0.815
5 (Standard)
Edit
Edit
Edit
NG 1
Info

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