Use a spreadsheet to generate a titration curve for 10.0 mL of 0.100 M CrO titrated with 0.100 M Ag+ to produce Ag₂ CrO4(s) (Ksp 1.20 x 10-¹2). Report the volume of Ag+ added at the following pAg+ values of the titration. =

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### Ion Concentration and Volume Calculation

In this exercise, we are calculating the volume of a solution required based on the pAg\(^+\) concentration.

#### Calculations:

1. **For pAg\(^+\) = 2.48:**
   - Calculated Volume: 19.99997 mL
   - Result: Incorrect

2. **For pAg\(^+\) = 1.90:**
   - Calculated Volume: 19.999998 mL
   - Result: Incorrect

Both of the calculated volumes did not match the expected correct value. This indicates either an error in the calculation approach or the input values. It is important to cross-check equations and assumptions used in deriving these volumes.

Please review your calculations to ensure accuracy.
Transcribed Image Text:### Ion Concentration and Volume Calculation In this exercise, we are calculating the volume of a solution required based on the pAg\(^+\) concentration. #### Calculations: 1. **For pAg\(^+\) = 2.48:** - Calculated Volume: 19.99997 mL - Result: Incorrect 2. **For pAg\(^+\) = 1.90:** - Calculated Volume: 19.999998 mL - Result: Incorrect Both of the calculated volumes did not match the expected correct value. This indicates either an error in the calculation approach or the input values. It is important to cross-check equations and assumptions used in deriving these volumes. Please review your calculations to ensure accuracy.
**Precipitation of Anions with Metal Cations**

Consider the precipitation of anion X\(^x\)- with metal cation M\(^n\)+:

\[ x\text{M}^{n+} + m\text{X}^{x-} \rightleftharpoons \text{M}_x\text{X}_m(\text{s}) \quad K_{sp} = [\text{M}^{n+}]^x[\text{X}^{x-}]^m \]

The following equation relates the volume of added M\(^n+\) (\(V_M\)) to [M\(^n+\)] and [X\(^x-\)] at a given point in the titration, and the initial volume of the X\(^x-\) solution (\(V_X^0\)), plus the initial concentrations of M\(^n+\) (\(C_M^0\)) and X\(^x-\) (\(C_X^0\)):

\[
V_M = V_X^0 \left( \frac{xC_X^0 + m[\text{M}^{n+}] - x[\text{X}^{x-}]}{mC_M^0 - m[\text{M}^{n+}] + x[\text{X}^{x-}]} \right)
\]

where \([\text{X}^{x-}] = \left( \frac{K_{sp}}{[\text{M}^{n+}]^x} \right)^{1/m}. \)

Use a spreadsheet to generate a titration curve for 10.0 mL of 0.100 M \(\text{CrO}_4^{2-}\) titrated with 0.100 M \(\text{Ag}^+\) to produce \(\text{Ag}_2\text{CrO}_4(\text{s})\) (\(K_{sp} = 1.20 \times 10^{-12}\)). Report the volume of \(\text{Ag}^+\) added at the following pAg\(^+\) values of the titration.
Transcribed Image Text:**Precipitation of Anions with Metal Cations** Consider the precipitation of anion X\(^x\)- with metal cation M\(^n\)+: \[ x\text{M}^{n+} + m\text{X}^{x-} \rightleftharpoons \text{M}_x\text{X}_m(\text{s}) \quad K_{sp} = [\text{M}^{n+}]^x[\text{X}^{x-}]^m \] The following equation relates the volume of added M\(^n+\) (\(V_M\)) to [M\(^n+\)] and [X\(^x-\)] at a given point in the titration, and the initial volume of the X\(^x-\) solution (\(V_X^0\)), plus the initial concentrations of M\(^n+\) (\(C_M^0\)) and X\(^x-\) (\(C_X^0\)): \[ V_M = V_X^0 \left( \frac{xC_X^0 + m[\text{M}^{n+}] - x[\text{X}^{x-}]}{mC_M^0 - m[\text{M}^{n+}] + x[\text{X}^{x-}]} \right) \] where \([\text{X}^{x-}] = \left( \frac{K_{sp}}{[\text{M}^{n+}]^x} \right)^{1/m}. \) Use a spreadsheet to generate a titration curve for 10.0 mL of 0.100 M \(\text{CrO}_4^{2-}\) titrated with 0.100 M \(\text{Ag}^+\) to produce \(\text{Ag}_2\text{CrO}_4(\text{s})\) (\(K_{sp} = 1.20 \times 10^{-12}\)). Report the volume of \(\text{Ag}^+\) added at the following pAg\(^+\) values of the titration.
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