Experiment 9.B amo S t ² mil 1-4 1 1 1 1 1 HCL 0.15 TITRATION A titrated with Volume of second reagent added (ml) 0.0 5.0 10.0 15.0 20.0 21.0 22.0 23.0 24.0 25.0 26.0 27.0 28.0 29.0 30.0 35.0 40.0 45.0 50.0 4. Nacht 2.1M PH 1.20 1,40 Name 1.54 1.83 2.64 7.18 2.3% 2.79 11.31 11,62 11.82 11.88 ANSWERS TO QUESTIONS 1. Titration A, endpoint pH= Titration B, endpoint pH= Why no K asked for Titration A? TITRATION B CH3c00H titrated with Na H AHM 0.1m Volume of second reagent added (mL) 0.0 5.0 10.0 15.0 20.0 21.0 22.0 23.0 24.0 25.0 26.0 27.0 28.0 29.0 30.0 35.0 40.0 45.0 50.0 Section 2. pk, or pk= 3. K, or K₂= PH 2-64 4.01 4.52 4.90 5.33 5.47 5.63 5.93 كل ما 10-10 11.36 41.65 11.82 1194 12.03 Pka = log ka ka = 10 -25 рка слики -3 Ka=1045 Ka=316x10 -5 H 0 5 10 ឧ. នជន៧៥៦ននន នន 15 20 21 22 23 24 25 26 27 28 29 30 0 5 10 15 20 21 22 23 24 25 26 27 28 29 30 1.19 1.2 1.4 1.54 1.83 1.93 2.04 2.18 2.38 2.79 9.89 11.31 11.62 11.82 11.88 2.64 4.01 4.52 4.9 5.33 5.47 5.63 5.93 6.48 10.1 11.36 11.65 11.82 11.94 12.03 Pla? 14 12 10 14 12 10 6 8 6 4 ². 0 pke = -log ke Ka = 10-25 ● 0 0 ● ● 5 5 10 pka=.10g ka ka = 10-45 10 F 'Field2' ● ● 15 15 'Field2' Field1 Field1 20 *....* 20 25 .... pH=7 ..... 30 pH=8.1 30

Appl Of Ms Excel In Analytical Chemistry
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ISBN:9781285686691
Author:Crouch
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Chapter2: Basic Statistical Analysis With Excel
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I need to make sure pKa/Ka significant digits are correct.
3
Experiment 9.B
amo
5
mt
onl
1m4
1
1
1
1
1
1
ни
0.10
TITRATION A
titrated with
Volume of second
reagent added (mL)
0.0
5.0
10.0
15.0
20.0
21.0
22.0
23.0
24.0
25.0
26.0
27.0
28.0
29.0
30.0
35.0
40.0
45.0
50.0
Nuot
2.1m
pH
1.19
1.20
1,40
Name
1.54
183
2.64
2.18
2.3%
2.79
9.89
11.31
11,62
11.82
11.88
ANSWERS TO QUESTIONS
1. Titration A, endpoint pH = 7
Titration B, endpoint pH=1
4. Why no K asked for Titration A?
TITRATION B
CH3c00+ titrated with Na H
0.1M
Volume of second
reagent added (mL)
0.0
5.0
10.0
15.0
20.0
21.0
22.0
23.0
24.0
25.0
Section
26.0
27.0
28.0
29.0
30.0
35.0
40.0
45.0
50.0
pH
2.64
4.01
4.52
4.90
5.33
5.47
5.63
5.93
601 48
10-10
11.36
41.65
11.82
1194
12.03
Pka = log ka
K² = 10-25
2. pk, or pK,=xa= 3.16.810.3
3. K, or K₂=
рка с лока
Ka=10-45
Ka= Bilpx 10
-5
1.
0
5
10
15
20
21
22.
23
24
25
26
27
28
29
30
០៣ ខ្ទពួន ជជនដងនឯគជាទ
0
5
10
15
20
21
22
23
24
25
26
28
29
1.19.
1.2
1.4
30
1.54
1.83
1.93
2.04
2.18
2.38
2.79
9.89
11.31
11.62
11.82
11.88
2.64
4.01
4.52
4.9
5.33
5.47
5.63
5.93
6.48
27 11.65
10.1
11.36
11.82
11.94
12.03
рка
phát
Y
14
12
10
-
6
14
12
2
0
10
8
6
4
2
2
0
pke = -log ke
Ka = 10-245
●
0
0
●
●
5
5
10
рказ.год Ка
3-4.5
ka = 10
10
1
'Field2'
●
●
15
15
'Field2'
Field1
Field1
20
20
25
25
pH=7
.....
30
pH=8.1
30
35
Transcribed Image Text:3 Experiment 9.B amo 5 mt onl 1m4 1 1 1 1 1 1 ни 0.10 TITRATION A titrated with Volume of second reagent added (mL) 0.0 5.0 10.0 15.0 20.0 21.0 22.0 23.0 24.0 25.0 26.0 27.0 28.0 29.0 30.0 35.0 40.0 45.0 50.0 Nuot 2.1m pH 1.19 1.20 1,40 Name 1.54 183 2.64 2.18 2.3% 2.79 9.89 11.31 11,62 11.82 11.88 ANSWERS TO QUESTIONS 1. Titration A, endpoint pH = 7 Titration B, endpoint pH=1 4. Why no K asked for Titration A? TITRATION B CH3c00+ titrated with Na H 0.1M Volume of second reagent added (mL) 0.0 5.0 10.0 15.0 20.0 21.0 22.0 23.0 24.0 25.0 Section 26.0 27.0 28.0 29.0 30.0 35.0 40.0 45.0 50.0 pH 2.64 4.01 4.52 4.90 5.33 5.47 5.63 5.93 601 48 10-10 11.36 41.65 11.82 1194 12.03 Pka = log ka K² = 10-25 2. pk, or pK,=xa= 3.16.810.3 3. K, or K₂= рка с лока Ka=10-45 Ka= Bilpx 10 -5 1. 0 5 10 15 20 21 22. 23 24 25 26 27 28 29 30 ០៣ ខ្ទពួន ជជនដងនឯគជាទ 0 5 10 15 20 21 22 23 24 25 26 28 29 1.19. 1.2 1.4 30 1.54 1.83 1.93 2.04 2.18 2.38 2.79 9.89 11.31 11.62 11.82 11.88 2.64 4.01 4.52 4.9 5.33 5.47 5.63 5.93 6.48 27 11.65 10.1 11.36 11.82 11.94 12.03 рка phát Y 14 12 10 - 6 14 12 2 0 10 8 6 4 2 2 0 pke = -log ke Ka = 10-245 ● 0 0 ● ● 5 5 10 рказ.год Ка 3-4.5 ka = 10 10 1 'Field2' ● ● 15 15 'Field2' Field1 Field1 20 20 25 25 pH=7 ..... 30 pH=8.1 30 35
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