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.3 Check Your Understanding Find the work done by the same force in Example 7.4 over a cubic path, y = (0.25 m-2)x³, between the same points A = (0, 0) and B = (2 m, 2 m). F = = (5 N/m)y i +(10 N/m)x j y(m)4 (2, 2) F(x, y) y(x), (0, 0) x(m) Figure 7.6 The parabolic path of a particle acted on by a given force.

.3 Check Your Understanding Find the work done by the same force in Example 7.4 over a cubic path, y = (0.25 m-2)x³, between the same points A = (0, 0) and B = (2 m, 2 m). F = = (5 N/m)y i +(10 N/m)x j y(m)4 (2, 2) F(x, y) y(x), (0, 0) x(m) Figure 7.6 The parabolic path of a particle acted on by a given force.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Find the work done by the force

 

 F→= (5 N/m)x i^ + (10 N/m)y j^

over a cubic path,
y = (0.25 m−2)x^3
 between the same points A = (0, 0) and B = (2 m, 2 m)
,

7.3 Check Your Understanding Find the work done by the same force in Example 7.4 over a cubic path, y = (0.25 m-2)x° , between the same points A (0, 0) and B = (2 m, 2 m). %3D F = (5 N/m)y i +(10 N/m)x j y(m)4 (2, 2) F(x, y) y(x), (0, 0) x(m) Figure 7.6 The parabolic path of a particle acted on by a given force.
Transcribed Image Text:7.3 Check Your Understanding Find the work done by the same force in Example 7.4 over a cubic path, y = (0.25 m-2)x° , between the same points A (0, 0) and B = (2 m, 2 m). %3D F = (5 N/m)y i +(10 N/m)x j y(m)4 (2, 2) F(x, y) y(x), (0, 0) x(m) Figure 7.6 The parabolic path of a particle acted on by a given force.
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