A dielectric slab of thickness b = between the plates of a parallel plate capacitor plate area A = 100 cm² and separation 0.50 cm and dielectric constant K=7, is placed d = 1 cm. A potential difference Vo=100V is applied with no dielectric present. The battery is then disconnected and the dielectric slab is inserted. Calculate the three electric vectors E, Ď and P in the dielectric,

A dielectric slab of thickness b = between the plates of a parallel plate capacitor plate area A = 100 cm² and separation 0.50 cm and dielectric constant K=7, is placed d = 1 cm. A potential difference Vo=100V is applied with no dielectric present. The battery is then disconnected and the dielectric slab is inserted. Calculate the three electric vectors E, Ď and P in the dielectric,

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter16: Electrical Energy And Capacitance

Section: Chapter Questions

Problem 6CQ: An air-filled parallel-plate capacitor with capacitance C0 stores charge Q on plates separated by...

See similar textbooks

Similar questions

The dielectric to be used in a parallel-plate capacitor has a dielectric constant of 3.60 and a dielectric strength of 1.60107 V/m. The capacitor has to have a capacitance of 1.25 nF and must be able to withstand a maximum potential difference 5.5 kV. What is the minimum area the plates of the capacitor may have?
What If? The two capacitors of Problem 13 (C1 = 5.00 F and C2 = 12.0 F) are now connected in series and to a 9.00-Y battery. Find (a) the equivalent capacitance of the combination. (b) the potential difference across each capacitor, and (c) the charge on each capacitor.
A capacitor has parallel plates of area 12 cm2 separated by 2.0 mm. The space between the plates is filled with polystyrene, (a) Find the maximum permissible voltage across the capacitor to avoid dielectric breakdown, (b) When the voltage equals the value found in part (a), find the surface charge density on the surface of the dielectric.
What is the maximum charge that can be stored on the 8.00-cm2 plates of an air-filled parallel-plate capacitor beforebreakdown occurs? The dielectric strength of air is 3.00 MV/m.
A parallel-plate capacitor with capacitance 5.0F is charged with a 12.0-V battery, after which the battery is disconnected. Determine the minimum work required to increase the separation between the plates by a factor of 3.
A parallel-plate capacitor with capacitance C0 stores charge of magnitude Q0 on plates of area A0 separated by distance d0. The potential difference across the plates is V0. If the capacitor is attached to a battery and the charge is doubled to 2Q0, what are the ratios (a) Cnew/C0 and (b) Vnew/V0? A second capacitor is identical to the first capacitor except the plate area is doubled to 2A0. If given a charge of Q0, what are the ratios (c) Cnew/C0 and (d) Vnew/V0? A third capacitor is identical to the first capacitor, except the distance between the plates is doubled to 2d0. If the third capacitor is then given a charge of Q0, what are the ratios (e) Cnew/C0 and (f) Vnew/V0?
An air-filled parallel-plate capacitor with capacitance C0 stores charge Q on plates separated by distance d. The potential difference across the plates is V0 and the energy stored is PEC,0. If the capacitor is disconnected from its voltage source and the space between the plates is then filled with a dielectric of constant = 2.00, evaluate the ratios (a) Cnew/C0, (b) Vnew/V0, and (c) PEC,new/PEC,0.
(a) Regarding (lie Earth and a cloud layer 800 m above the Earth as the plates of a capacitor, calculate the capacitance of the Earth-cloud layer system. Assume the cloud layer has an area of 1.00 km2 and the air between the cloud and the ground is pure and dry'. Assume charge builds up on the cloud and on the ground until a uniform electric field of 3.00 106 N/C throughout the space between them makes the air break down and conduct electricity as a lightning bolt, (b) What is the maximum charge the cloud can hold?
A parallel-plate capacitor has charge of magnitude 9.00F on each plate and capacitance 3.00F when there is air between the plates. The plates are separated by 2.00 mm. With the charge on the plates kept constant, a dielectric with =5 . is inserted between the plates, completely filling the volume between the plates, (a) What is the potential difference between the plates of the capacitor, before and after the dielectric has been inserted? (b) What is the electrical field at the point midway between the plates before and after the dielectric is inserted?
(a) Find the equivalent capacitance between points a and b for the group of capacitors connected as shown in Figure P16.46 if C1 = 5.00 F, C2 = 10.00 F, and C3 = 2.00 F. (b) If the potential between points a and b is 60.0 V, what charge is stored on C5? Figure P16.46
An air-filled capacitor is made from two flat parallel plates 1.0 mm apart. The inside area of each plate is 8.0cm2. (a) What is the capacitance of this set of plates? (b) If the region between the plates is filled with a material whose dielectric constant is 6.0, what is the new capacitance?
An electric potential exists in a region of space such that V = 8x4 2y2 + 9z3 and V is in units of volts, when x, y, and z are in meters. a. Find an expression for the electric field as a function of position. b. What is the electric field at (2.0 m, 4.5 m, 2.0 m)?