. You have 44.3 mg of the radioactive isotope 1311. How long will it take for the amount of 1311 to drop to 15.3 mg? 131 has a half-life of 8.02 days. A) 8.02 days B) 12.3 days C) 23.5 days D) 10.8 days E) 19.8 days Write a nuclear equation for the alpha decay of Am-241. A) 24 Am → He + ½/He + 233Np B) 24 Am → He + 245Bk 97 -je + 241 Cm C) 245Am → →e+ D) 241-3 Am → ₁e + 241 Pu → 94 241 95 E) 29-Am Am → → 1/1/n + În + 240 Am
. You have 44.3 mg of the radioactive isotope 1311. How long will it take for the amount of 1311 to drop to 15.3 mg? 131 has a half-life of 8.02 days. A) 8.02 days B) 12.3 days C) 23.5 days D) 10.8 days E) 19.8 days Write a nuclear equation for the alpha decay of Am-241. A) 24 Am → He + ½/He + 233Np B) 24 Am → He + 245Bk 97 -je + 241 Cm C) 245Am → →e+ D) 241-3 Am → ₁e + 241 Pu → 94 241 95 E) 29-Am Am → → 1/1/n + În + 240 Am
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question

Transcribed Image Text:. You have 44.3 mg of the radioactive isotope 1311. How long will it take for the amount of 1311 to drop to
15.3 mg? 131 has a half-life of 8.02 days.
A) 8.02 days
B) 12.3 days
C) 23.5 days
D) 10.8 days
E) 19.8 days
Write a nuclear equation for the alpha decay of Am-241.
A) 24 Am → He +
½/He + 233Np
B) 24 Am → He + 245Bk
97
-je + 241 Cm
C) 245Am → →e+
D) 241-3 Am → ₁e + 241 Pu
→
94
241
95
E) 29-Am
Am →
→
1/1/n +
În + 240 Am
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