The answer that was given i already had the answer so I'm not sure why u guy's did the same one?...can u do problem #2. I don't need problem 1. Please give me credit for the one you answer wrong. Thank you Zoom Day 10 Sp 21and 2 rally occurring chlorine that is put in pools is 75,53 percent "CI (mass = 34.969 amu)und 24.47 percent "CI (mass = 36 966 amu) Calculate the average atomic mass of chlorine.(34.969 amux 0.7553)+(26.966amuX 62447) 35.46amy=26414 9.046- 1GMTdmic muss =2. Titanium has five common isotopes: 46TI (8.00%. 45.983 amu), 47Ti (7.80%, 46.988 amu), *I(75.4%, 47.910 amu), 4°TI (5.50%, 48.923 amu), 50Ti (5.30%, 49 942 amu). What is the averageatomic mass of titanium?3. Silver has two naturally occurring isotopes (Ag-107 and Ag-109).a. Use the periodic table to find atomic mass of silverb. If the natural abundance of Ag-107 is 51,84%, what is the natural abundance of Ag-109?c. If the mass of Ag-107 is 106.905 amu, what is the mass of Ag-109?10787 amub)100-51.84%-48.1680atemic mass= (wuss,x aburdance )+ (mass + abundance)5!.84T01.87=C106.90s amu x 0.5184)mass XO.4816)167-87 =5542t Cmass xo.4816)-5542-5542I08.91 amu = MasS5245 amuニルASS XO48/60.48144814Write the formula for eachFormulaHydronitric acidchromium (I) phosphitesilver oxalatedifluorine monoxide5. Write the name of each of these based on the formulaNameHIO,SNPO4PFsNi(NO:)3

Answered: . Titanium has five common isotopes:…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Concept explainers

Question

The answer that was given i already had the answer so I'm not sure why u guy's did the same one?...can u do problem #2. I don't need problem 1. Please give me credit for the one you answer wrong. Thank you

Zoom Day 10 Sp 21
and 2 rally occurring chlorine that is put in pools is 75,53 percent "CI (mass = 34.969 amu)
und 24.47 percent "CI (mass = 36 966 amu) Calculate the average atomic mass of chlorine.
(34.969 amux 0.7553)+
(26.966amuX 62447) 35.46amy
=26414 9.046- 1GMT
dmic muss =
2. Titanium has five common isotopes: 46TI (8.00%. 45.983 amu), 47Ti (7.80%, 46.988 amu), *I
(75.4%, 47.910 amu), 4°TI (5.50%, 48.923 amu), 50Ti (5.30%, 49 942 amu). What is the average
atomic mass of titanium?
3. Silver has two naturally occurring isotopes (Ag-107 and Ag-109).
a. Use the periodic table to find atomic mass of silver
b. If the natural abundance of Ag-107 is 51,84%, what is the natural abundance of Ag-109?
c. If the mass of Ag-107 is 106.905 amu, what is the mass of Ag-109?
10787 amu
b)100-51.84%-48.1680
atemic mass= (wuss,x aburdance )+ (mass + abundance)5!.84
T01.87=C106.90s amu x 0.5184)mass XO.4816)
167-87 =5542t Cmass xo.4816)
-5542
-5542
I08.91 amu = MasS
5245 amuニルASS XO48/6
0.4814
4814
Write the formula for each
Formula
Hydronitric acid
chromium (I) phosphite
silver oxalate
difluorine monoxide
5. Write the name of each of these based on the formula
Name
HIO,
SNPO4
PFs
Ni(NO:)3

Expert Solution

Data given:

Note: If you do not mention the questions that need to be solved, the answer provider will automatically choose the first one , no matter if you have asked solution for it or not.

Please find the answer to question no. 2 here:

a. Isotope I of titanium = ${}^{46}T i$

Percentage abundance of ${}^{46}T i$ isotope = 8.00 %

Atomic mass of ${}^{46}T i$ isotope = 45.983 amu

b. Isotope II of titanium = ${}^{47}T i$

Percentage abundance of ${}^{47}T i$ isotope = 7.80 %

Atomic mass of ${}^{47}T i$ isotope = 46 .988 amu

c. Isotope III of titanium = ${}^{48}T i$

Percentage abundance of ${}^{47}T i$ isotope = 73.40 %

Atomic mass of ${}^{47}T i$ isotope = 47.910 amu

d. Isotope IV of titanium = ${}^{49}T i$

Percentage abundance of ${}^{49}T i$ isotope = 5.50 %

Atomic mass of ${}^{49}T i$ isotope = 48.923 amu

e. Isotope V of titanium = ${}^{50}T i$

Percentage abundance of ${}^{50}T i$ isotope = 5.30 %

Atomic mass of ${}^{50}T i$ isotope = 49.942 amu

Note:

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions