. A wire 0.5 m long and mass 5 x 10³ kg is stretched such that its fundamental frequency of transverse vibration is 100 Hz. Find the tension in the wire. How will you double the frequency by changing the vibrating length ?
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A wire 0.5 m long and mass 5 × 10-³ kg is
stretched such that its fundamental frequency
of transverse vibration is 100 Hz. Find the
tension in the wire. How will you double the
frequency by changing the vibrating length ?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdd0b9a0e-f3d0-40d3-876b-282f27702b26%2F44cf4809-350f-415d-b493-1c3d0cbbea3b%2F8whgdf_processed.jpeg&w=3840&q=75)
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- The human eardrum responds to sound by vibrating. If the eardrum moves in simple harmonic motion at a frequency of 2.88 kHz and an amplitude of 0.132 nm, what is its maximum speed of vibration?A string has length 2.0 m, tension 60 N, and linear density 0.080 kg/m. The left end of the string is connected to a massless ring that slides on a frictionless pole, and the ring is attached to a spring of stiffness 150 N/m. The right end is attached to a massless ring that slides on a frictionless pole. The left end of the string is driven by a transverse force of amplitude 4.0 N and frequency 21 Hz. F(t) S x = 0 x = L 2. The input mechanical impedance (at x = 0) is Zmo = s/im + ipLc tan(kL). Using established impedances (do not calculate), explain why the input impedance is given by this expression. Evaluate the impedance for the specified values of the system. Be sure to show the units. Note: In the computation of the tangent, do not round off the value of k. From the value of the impedance, determine the steady-state velocity amplitude (in m/s) of the left ring.3
- 19. A particle of mass m is undergoing forced vibration under the action of a restoring force, a damping force and an external periodic force. If s be the restoring force constant, Rm be the damping force per unit velocity then the amplitude resonant frequency will be Select one: a. (1/2π)√[(s/m) – (Rm2/4m2)] b. (1/2π)√[(s/m) + (Rm2/4m2)] c. (1/2π)√[(s/m) – (Rm2/2m2)] d. (1/2π)√(s/m)The midpoint of a guitar string executes simple harmonic motion with motion following the form x(t) = A sin(wt + p). It has an angular frequency of w = 2.65 × 10³ s-¹ and an amplitude of A = 1.50 mm. Take the phase constant to be p = π/2.The tip of a tuning fork goes through 420 complete vibrations in a time of 0.440 s. What is the angular frequency?
- A 0.500 kg stone is moving in a vertical circular path attached to a string that is 75.0 cm long. The stone is moving around the path at a constant frequency of 2.20 rev/sec. At the moment the stone is overhead, the stone is released. The velocity of the stone when it leaves the circular path is Multiple Choice 10.4 m/s horizontal. 10.4 m/s vertical. 22.0 m/s horizontal. 22.0 m/s vertical. 31.4 m/s horizontal.IC-3 A 167 gram mass is vibrating about its equilibrium position on the end of a spring as shown in problem SHM-8. While vibrating, the mass is observed to have a maximum speed of 0.500m/s and a maximum acceleration of 6.00m/s. At t0 the mass is at the equilibrium position with a velocity to the left. a) Find the numerical values for the angular frequency o and the amplitude of the motion xm. Hint: think about how Vm and xm are related. b) Find the value of the spring constant of the spring. c) The position of the block is described by x Xmcos(@t+0,). Find all possible values of 0, and then explain how to determine the value of 0, that corresponds to the given conditions. 99+ hpFind the personal frequency, shape mode and vibration response equation of the above system, if K1 250 N / m, K2 = 250 N / m =, K3 = 300 N / m, K4 = 350 N / m = K5 = 200 N / m
- A spring stretches by .0174 when a 2.66 kg object is suspened from its end. How much mass should be attached to this spring such that its frequency is f=4.53 hzQuestion 1: X-ray Diffraction x-ray diffraction is a method used to identify different types of materials. While this is usually quite a complex process, however for a simple cubic structure, as seen below, we can find the distance between neighboring atoms. The below image shows the diffraction of x-rays passing through a cubic structure and illustrates a change in distance of 2d sine Light rays in phase ● a /I\ 100 20. b d sin 8 2d sin 0 Atoms in crystal If the wavelength of the x-ray is equal to an integer multiple of this change in distance, we will get constructive interference: mλ = 2d sine X-rays of wavelength 0.103 nm reflects off a crystal and a second-order maximum is recorded at a Bragg angle of 25.5°. (a) What is the spacing between the scattering planes in this crystal? (b) At what angle will the third-order maximum occur?A 0.417 kg mass is attached to a string with a force constant of 53.9 N/m. The mass is displaced 0.286m from equilibrium and released. Assuming SHM for the system. Part A: With what frequency does it vibrate ? Part B: What is the speed of the mass when it is 0.143m from equilibrium? Part C: What is the total energy stored in this system? Part D: What is the ratio of the kinetic energy to the potential energy when it is at 0.143m from equilibrium?