HW3 completed

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Statistics

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Apr 3, 2024

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Assignment 3 Read the assignment, complete the required steps within SPSS, and create a full write up of what was found. Make sure to turn in both the SPSS output as well as the write up. These two things can be put together into one file but make sure they are not overlapped and are clearly separated. Required SPSS steps (use the SPSS walkthrough as assistance) (5pts) - Run normality tests on sleep and Homework Completed. - Do 2 Independent Sample T sample t tests; SES (Socio Economic Status) as the IV (factor) for each test and Sleep and Homework completed as Dependent Variables. - Make sure to check homogeneity of variance for each independent T test. - Next Run a correlation between sleep and HW_completed and Sleep. - Finally run a Chi Square between Pokémon type and SES. Required steps for a SPSS Write up (5pts) - Describe whether the assumption of normality and homogeneity were met and how you know that. Tests of Normality Kolmogorov-Smirnov a Shapiro-Wilk Statistic df Sig. Statistic df Sig. Sleep .122 100 .001 .953 100 .001 HW_completed .192 100 .000 .861 100 .000 a. Lilliefors Significance Correction - The assumption of normality for sleep was not met via the use of the Shapiro-Wilks test, W (100) = .953, p < .05. - The assumption of normality for homework completed was not met via the use of the Shapiro-Wilks test, W (100) = .861, p < .05. Levene's Test for Equality of Variances F Sig. Sleep Equal variances assumed 1.053 .307 Equal variances not assumed

- The assumption of homogeneity for sleep was met via the Leven’s test, F = 1.053, p > .05, therefore the variances between the low and high SES is the same in regards to sleep. Levene's Test for Equality of Variances F Sig. HW_completed Equal variances assumed 26.895 .000 Equal variances not assumed - - The assumption of homogeneity for homework completed was not met via the Leven’s test, F = 26.895, p < .05, therefore the variances between the low and high SES is not the same in regards to homework completed. - Give an interpretation of the results with the correct statistical format for each analysis.. o What type of correlation was it and explain in words an example of the relationship Correlations Sleep HW_completed Sleep Pearson Correlation 1 .967 ** Sig. (2-tailed) .000 N 100 100 HW_completed Pearson Correlation .967 ** 1 Sig. (2-tailed) .000 N 100 100 **. Correlation is significant at the 0.01 level (2-tailed). - There is a significant positive relationship between hours of sleep and homework’s completed, r (98) = .967, p < .05, therefor as sleep increases homework’s completed increase. o Inform the direction of the independent T test (so what group is bigger) t-test for Equality of Means

t df Sig. (2-tailed) Mean Difference Std. Error Difference 95% Confidence Interval of the Difference Lower Upper -7.308 98 .000 -2.22000 .30379 -2.82285 -1.61715 - There is a significant difference in sleep between low SES and high SES individuals, D = -2.22, t(98) = -7.308, p < .05, CI = (-2.8, -1.6). This means that the Low SES group gets less sleep than the higher SES. t-test for Equality of Means t df Sig. (2-tailed) Mean Difference Std. Error Difference 95% Confidence Interval of the Difference Lower Upper -6.938 98 .000 -2.40000 .34591 -3.08646 -1.71354 - There is a significant difference in homework’s completed between low SES and high SES individuals, D = -2.4, t (98) = -6.938, p < .05, CI = (-3, -1.7). This means that Low SES individuals complete less homework than High SES individuals. o Rationalize the chi square - Chi-Square Tests Value df Significance (2- sided) Pearson Chi-Square 2.877 a 3 .411 - A person preferred Pokémon type and their SES are independent of one another, X- square (3) = 2.87, p > .05, therefore SES does not determine ones Pokémon preference. - Interpret the effect size, mean differences, and confidence interval for each test. EFFECT SIZE - The effect size between sleep and homework is .94. o Therefore 94% of any increase in sleep is caused by any increase in homework’s completed.

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o Therefore 94% of any increase in homework completed is caused by any increase in sleep. o Therefore 94% of a person’s sleep is due to their completed homework’s. o Therefore 94% of a person’s sleep is due to their completed homework’s. o Therefore 94% of the variability within sleep is due to homework. o Therefore 94% of the variability within sleep is due to homework. CONFIDENCE INTERVAL If this test was ran an infinite number of times there will always be a significant difference between Low and High SES in regards to sleep and homework.