Find the critical value for

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Find the critical value for - to ( negative t subcript zero), two tailed test with Alpha=0.10 and n=26 ◦ a. - 1.708 ◦ b. + 1.725 ◦ c. + 1.708 O d. - 1.725 Calculate Z=0.05 ◦ а. 0.985 ◦ b. 2.47 ◦ c. 0.0129 O d. 1.645 What type of error occurs if you fail to reject Ho when, in fact, it is not true? ◦ Type lI ◦ Type I either Type I or Type II, depending on the level of significance either Type I or Type II, depending on whether the test is one-tailed or two-tailed A manager of a shoe company says that the Mean life of their shoes is more than 4 years. What is the Null and Alternative hypothesis? O a. Ho: M= 4 Question 4 of 16 > 2 points Saved O b. Ho: u>4 Ha:<4 O c. Ho: u<4 Ha: M > 4 O d. Ho: M≥4 Ha: M > 4 Read the z statistic from the normal distribution table and choose the correct answer. For a one-tailed test (upper tail) using a = .0721, z=? 0 1.54 ◦ 1.46. ◦ 1.96. 1.645. The mean price of a Honda motor cycle is $ 5,000. There is a claim that this idea is incorrect and for that we found a sample of 12 motorcycles with a mean price of $ 4,800 and standard deviation of $ 300. What test do you use and what is your test statistic result? O a. T-test, -2.30 ◦ b. T-test. 1.708

◦ c. Z-test. 1.96 d. Z-test, -. 1.78 In general, If P value is greater that 0.05, the test is not significant and we fail to reject the null hypothesis. ◦ True False York University announces that the proportion of their students who are involved in a sporting event is 40%. What is the Null and alternative hypothses. O a. Ho: M > 40 Ha: M <40 O b. Ho: M> 220 Ha: 4 < 220 O c. Ho: M = 40 Ha: M # 40 O d. Ho: u ≥40 Ha: M > 40 In this formula which letter represents the confidence level value? S I =×** In 2 points L Saving Answer O a. Square root of n © b.Z O c.X bar O d. s The probability of making a Type I error is denoted by B. © True • False A production line operates with a mean filling weight of 16 ounces per container. Overfilling or underfilling presents a serious problem and when detected reguires the operator to shut down the production line to readjust the filling mechanism. From past data, a population standard deviation o=.8 ounces is assumed. A quality control inspector selects a sample of 30 items every hour and at that time makes the decision of whether to shut down the line for readjustment. The level of significance is a=.05. If a sample mean of x (X bar) =16.32 ounces were found, what is the p-value? What action would you recommend? O a. .0286. p-value 5 .05; reject Ho. Readjust production line. ◦ b..0143, p-value s .05; reject Ho. Readjust production line. ◦ c..0143, p-value 5 .05; fail to reject Ho. Readjust production line.

d. .0286, p-value 5 .05; fail to reject Ho. Readjust production line. Two independent simple random samples are taken to test the difference between the means of two populations whose standard deviations are not known, but are assumed to be equal. The sample sizes are n1 = 25 and n2 = 30. The correct distribution to use is the t distribution with degrees of freedom. © a. 53 06 54 O c.57 0 d. 56 If the Alternative hypothesis Ha contains the not equal symbol then the hypothsis test is a two tailed test. ◦ True False Salary information regarding male and female employees of a large company is shown below. Sample Size Sample Mean Salary (in $1000) Population Variance (82) Male 64 45 128 Female 36 41 72 At 95% confidence, the margin of error is ....... • a.3.920 0 6. 7.839. ◦ c. 1.960. d. 1.645. A production line operates with a mean filling weight of 16 ounces per container. Overfilling or underfilling presents a serious problem and when detected requires the operator to shut down the production line to readjust the filling mechanism. From past data, a population standard deviation o=.8 ounces is assumed. A quality control inspector selects a sample of 30 items every hour and at that time makes the decision of whether to shut down the line for readjustment. The level of significance is a=.05. State the hypothesis test for this quality control application.

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O a. Ho: y > or equal to 16 Ha: M < 16 Ob. Ho: M < 16 Ha: M > 16 O c. Ho: M = 16 Ha: u # 16 O d.Ho: M # 16 Ha: M = 16 The critical value oft for a two-tailed test with 10 degrees of freedom using a = .05 is O a. 2.228 ◦ b. 1.812 ◦ c. 1.833 d. 2.262

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