PostLab 6_ Conservation of Momentum
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School
University of Nevada, Las Vegas *
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Course
180L
Subject
Physics
Date
Apr 3, 2024
Type
Pages
7
Uploaded by ProfDragonflyPerson376
Name
: Miguel Rivera Villareal
Lab/Section:
Physics 180L 1009
Teaching Assistant:
Nuzhat Nuari Islam
Due Date:
November 4th, 2022
Conservation of Momentum
Objective:
To understand the law of conservation of momentum via colliding objects in two
dimensions.
Apparatus:
Digital scale, ramp, two steel balls, one hollow steel ball, C-clamp, plumb bob,
sheet of easel paper, masking tape, meter stick, protractor, carbon paper
Theory:
The general formula that defines conservation of momentum would be that
momentum equates to mass times velocity, allowing for additional objects that collide to be
simply added. It is important to note that since velocity is a vector, the directions are
significant before and after the collision.
If an object at rest is struck with an object of same mass the resulting objects will depart from
one another with a 90 degree angle.
When rolling a ball down a ramp off a table the vertical component of velocity is active until
it hits the ground, so the distance from when the ball leaves the table and hits the ground can
be measured using the velocity and time. If masses are the same they can be ignored in the
momentum equation, leaving just the velocities to be added or the distances of the collided
objects can be used instead if they’re known.
Procedure:
Part one of the lab is searching for the aforementioned distance. Before doing so,
set up the lab environment by securing the ramp system, taping paper to the ground near the
ramp, aligning the plumb bob to the center of the paper, marking this point, and marking
where a ball rolling down hits the paper. Repeat the rolling ball action ten times to get an
estimated likely position for where the ball will drop and then mark the center of the 10
droppings. Connect the new mark with a line to the plumb and record the length of this line.
Encase the 10 drop points in a circle.
To determine the distances of the colliding objects, one must first set the other steel ball on
the collision plate’s first depression. Replace the locations where the ball lands with carbon
paper, for another 10. Repeat the line drawing procedure that was previously mentioned for
this new set of collisions while also documenting the length of lines, angles between the new
lines and the first line. Label the impact patterns as S
₁
ₐ S
₁
в.
Part B consists of repeating with the target in the second depression and label this new set
with S
₂
ₐ and S
₂
в with part C doing it again but making the target instead a hollow or plastic
ball in any depression, labeling it as S
₃
ₐ and S
₃
в.
For the final section, the report, get the ratio of masses between the hollow/plastic ball and
the steel ball. Then, for each collision that had two steel balls, add the Sₐ Sв vectors via
graphical or analytical method and compare it to the original S length., though if the latter
method is chosen add a diagram. Repeat this for the hollow/plastic ball collision but multiply
the B vector by the ratio. The last step is getting the percent errors for all the x-components
and angles in relation to 90 degrees.
Equations:
[|(S
Ax
+ S
Bx
) - S | / S] * 100% = percent difference of lengths
S = S
A1
+ S
B1
S = S
A2
+ S
B2
S = S
A3
+ (M
B
/M
A
) * S
B3
S
Ax,
S
A1,
S
A2,
S
A3
: incident ball’s x-axis length in centimeters
S
Bx,
S
B1,
S
B2,
S
B3
:
collision ball’s x-axis length in centimeters
M
B
: hollow ball’s mass in grams
M
A
: steel ball’s mass in grams
[ |(Θ
A
+ Θ
B
) - 90
°
| / 90
°
]
* 100 % = percent difference of angle
Θ
A
: incident ball’s angle
Θ
B
:
collision ball’s angle
Data:
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Related Questions
Learning Goal:
To understand the relationship between force, impulse,
and momentum.
The effect of a net force EF acting on an object is
related both to the force and to the total time the force
acts on the object. The physical quantity impulse J is a
measure of both these effects. For a constant net force,
the impulse is given by
J = FAt.
The impulse is a vector pointing in the same direction as
the force vector. The units of J are N. sor kg · m/s.
Recall that when a net force acts on an object, the object
will accelerate, causing a change in its velocity. Hence
the chiect's momentum in- mail will also change. The
Figure
F (N)
L
12,000
0.0007
1 of 1
t (s)
In Parts A, B, C consider the following situation. In a baseball game the batter swings and gets a good solid hit. His swing applies a force of 12,000 N to the ball for a
time of 0.70 × 10-³ s.
Part A
Assuming that this force is constant, what is the magnitude J of the impulse on the ball?
Enter your answer numerically in newton…
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p = mv
J = Ft
Ft = m Av
Calculate the change in momentum of a 0.5 kg ball that strikes the floor at 15 m/s
and bounces back up at 12 m/s.
N
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QUESTION 42
You are measuring the final momentum of two objects that stick together after colliding in an experiment. In several trials, you obtain the following values in kg·m/s: [20,24,32,17,15,26,24,27,40,36].
(b) In Excel, enter the data in a column and find the standard deviation and report the answer below and round up to the nearest whole number for example 13.99 would be 14. 14.32 would be 14.
arrow_forward
C Calculator X
O * Dashboard | Khan Academy x
A Week 6 Physics Quiz Impulse, x
E Week 6 Ph
LSdGd-dk1 DxxEx8sLZMSsGLCYS3uVGMsC StoTTKbm-mqCLvgw/viewform?hr_submission=DChkl403_3.
Period 2-Physics
1. a) What is the momentum of a 5-kg bowling ball rolling at 4 m/s? b) If
the bowling ball rolls into a pillow and stops in 1.5 s, calculate the average
force on the pillow. c) What average Force does the pillow exert on the
vectors required.
30 points
ball. SKETCHES with
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1. Which of the following statements is/are TRUE?
a. The coefficient of restitution can take up a value greater than 1.
b. The center of mass can be located outside the object, especially those with
curved structures.
c. The initial momentum of a moving body is directly proportional to the force
applied and to the duration of its application.
d. The final velocities of two colliding objects can be calculated if the coefficient of
restitution is given along with the objects' initial velocities.
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1) A 100 g cart initially moving at +0.5 m/s collides elastically from a stationary 180 g cart.
a) Using the equation in the theory, calculate the final velocity of the 100 g cart.
b) Calculate the change in the momentum of the 100 g cart.
c) Since this is an elastic collision, total momentum must be conserved. Using your answer
for part b, calculate the final velocity of the 150 g cart.
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(a) What is the mass of a large ship that has a momentum of 1.40 x 109 kg-m/s, when the ship is moving at a speed of
38.0 km/h?
1.327
X kg
(b) Compare the ship's momentum to the momentum of a 1400 kg artillery shell fired at a speed of 1300 m/s.
P ship
769.23
Pshell
Additional Materials
MReading
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4. Define and illustrate a general collision of two objects in two-dimensional space.
Please define the conservation of total momentum and energy of the system in each direction.
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21
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SC
24: Module 4
Assignment Booklet 48
For questions 17 to 21, read each question carefully. Decide which of the choices
BEST answers the question. Place your answer in the blank space given.
17. Two vehicles with the same mass and travelling the same speed in
opposite directions hit head on. What is the total momentum immediately
after the collision?
A. zero
B. double that of each car
C. one half that of each car
D. four tirnes that of each car
Use the following diagram to answer questions 18 and 19.
Car B
Car A
nt Bookl
ence 24
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Determine the location of the center of mass of the system shown in the figure.
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a) What impulse occurs when an average force of 10 N is exerted on a cart for 2.5 s? b. What change in momentum does the cart undergo? c. If the mass of the cart is 2 kg and the cart is initially at rest , calculate its final speed.
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solve as follows:
1. given
2. unknown
3. equation
4. solution
5. answer
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34. In trial 1 of an experiment, a cart moves with
speed vo on a frictionless, horizontal track and
collides elastically with another cart that is
initially at rest. In trial 2, the setup is identical
except that the carts stick together during the
collision. How does the speed of the two-cart
system's center of mass change, if at all, during
the collision in each trial?
Trial 1
Trial 2
(A) Does not change
(B) Does not change
C) Decreases
(Đ) Decreases
Does not change
Decreases
Does not change
teg Decreases
(A)
ganga
oold sd
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9:07 fing n
O O X * ll 71%
Pearson
https://openvellum.ecollege.com/cou.
Course Home
(MP11-19: Momentum and Impulse
221-16-3
3 of 4
I Review | Constants
Part A
Use the impulse-momentum theorem to find how long
a falling object takes to increase its speed from 5.60
m/s to 11.0 m/s.
ΑΣΦ
S
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Directions: Select whether the statement is true of false.
1. As the ball rises, it decreases its vertical velocity.2. The projectile experiences a constant vertical acceleration due to the pull of gravity as it rises and falls.3. Collision conserved momentum.4. The total time (t’) of flight is simply double the time it takes for the projectile to rise.5. Perfectly inelastic collision is described by maximum lost in kinetic energy.6. Elastic collision happens when 2 objects stick together after collision.7. Elastic collision conserved kinetic energy.8. The time it takes to rise to its highest point is longer than the time it takes to fall. 9. Kinetic energy is conserved in all kinds of collision.10. The horizontal distance known as the range, R of the projectile is the ratio of the horizontal velocity and the total time of flight.
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Hi, please show full solutions and also explain how you get the answers in physics terms so it's understandable. The correct final answers are written beside too. This is one whole question to be answered. I can't post it separately since it's related. Thank you.
12. A stationary 6.0 kg object blows apart into 3 pieces. The 3 pieces move away from each other on a level plane. A 2.0 kg piece moves away at 3.0 m/s [30.0º W of N] and a 1.0 kg piece moves away at 5.0 m/s [25º N of W].a) Draw a labelled vector diagram of the system after the explosion. Include all known angles, masses and speeds.b) Determine the velocity of the third piece. (3.5 m/s [44º S of E])
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QUESTION 41
You are measuring the final momentum of two objects that stick together after colliding in an experiment. In several trials, you obtain the following values in kg·m/s: [20,24,32,17,15,26,24,27,40,36].
(a) In Excel, enter the data and find the mean and report the answer below. Please round up to the nearest whole number, for example 13.99 would be 14. 14.32 would be 14 etc.
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How do you get this answer?
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A 50 kg mass is sitting on a frictionless surface. An unknown constant force pushes the mass for 2 seconds until the mass reaches a velocity of 3 m/s.
a) What is the initial momentum of the mass?b) What is the final momentum of the mass?c) What was the force acting on the mass?d) What was the impulse acting on the mass?
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4. You need to show your work in detail to get any credit.
Before collision:
The red car (on the left) has the velocity of
10.0 m/s and mass of 4.8 kg.
The blue car (on the right) has the velocity
of -5.6 m/s and mass of 4.4 kg.
After elastic collision:
The blue car moves with the velocity of 8.8 m/s.
(a) What is the initial momentum of the red car?
(b) What is the initial momentum of the blue car?
(c) What is the total momentum of the system of blue and red car before collision?
(d) What is the final momentum of the blue car?
(e) What is the impulse on the blue car (in kg.m/s)?
(f) Is the system consisting of the blue and red car an isolated system?
(g) What is the impulse on the red car (in kg.m/s)?
(h) What is the velocity of the red car after the collision?
(i) Draw annotated p-t and F-t graphs for both carts at all stages of collision. Assume that
collision occurred for 0.5 seconds.
Before
Р
Ft
During
+X
After
24
t
4
t
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The brakes on a 15,680 N car exert a stopping force of 640. N. The car’s velocity changes from 20.0 m/s to 0 m/s.
a) What is the car’s mass?
b) What was its initial momentum?
c) What was the change in momentum for the car?
d) How long does it take the braking force to bring the car to rest?
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2 The shown square plate is made from two
different materials vith densities of pi and p2
respectively with negligible thickness.
If pr: P2 1:3 find the center of mass.
За
Pi
P2
За
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Activity 4:
Solve the following problems.
A 2600 kg SUV traveling west at 15 m/s collides head on with 1300 kg sedan traveling east
at 20 m/s. Determine the speed and direction of the two cars immediately after impact
if they lock together?
1.
Before Collision
After Collision
Object A
Mass =
Mass =
Velocity =D
Total Momentum%3Dmass x velocity
Velocity =
Total
Momentum3Dmass
velocity
P3mv
P=mv
Object B
Mass =
Mass =
Velocity =
x Total Momentum3Dmass x velocity
Velocity =
Total
Momentum3mass
velocity
P=mv
P=mv
Total
Total Momentum
Total Momentum
(MaxVb)+(MpxV)=
The Deşired Equation for the Problem/Solution
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Related Questions
- Learning Goal: To understand the relationship between force, impulse, and momentum. The effect of a net force EF acting on an object is related both to the force and to the total time the force acts on the object. The physical quantity impulse J is a measure of both these effects. For a constant net force, the impulse is given by J = FAt. The impulse is a vector pointing in the same direction as the force vector. The units of J are N. sor kg · m/s. Recall that when a net force acts on an object, the object will accelerate, causing a change in its velocity. Hence the chiect's momentum in- mail will also change. The Figure F (N) L 12,000 0.0007 1 of 1 t (s) In Parts A, B, C consider the following situation. In a baseball game the batter swings and gets a good solid hit. His swing applies a force of 12,000 N to the ball for a time of 0.70 × 10-³ s. Part A Assuming that this force is constant, what is the magnitude J of the impulse on the ball? Enter your answer numerically in newton…arrow_forwardCourse Home ecollege.com/course.html: 16258302&HepID%3Dfc40f7be012937edeef713dc4972732c#10001 品☆ Provide Feedback P Pearson 758 AM Copyright © 2020 Pearson Education Inc. All rights reserved. Terms of Use I Privacy Policy I Permissions I Contact Us (? 10/14/2020arrow_forwardNeed answer asaparrow_forward
- p = mv J = Ft Ft = m Av Calculate the change in momentum of a 0.5 kg ball that strikes the floor at 15 m/s and bounces back up at 12 m/s. Narrow_forwardQUESTION 42 You are measuring the final momentum of two objects that stick together after colliding in an experiment. In several trials, you obtain the following values in kg·m/s: [20,24,32,17,15,26,24,27,40,36]. (b) In Excel, enter the data in a column and find the standard deviation and report the answer below and round up to the nearest whole number for example 13.99 would be 14. 14.32 would be 14.arrow_forwardC Calculator X O * Dashboard | Khan Academy x A Week 6 Physics Quiz Impulse, x E Week 6 Ph LSdGd-dk1 DxxEx8sLZMSsGLCYS3uVGMsC StoTTKbm-mqCLvgw/viewform?hr_submission=DChkl403_3. Period 2-Physics 1. a) What is the momentum of a 5-kg bowling ball rolling at 4 m/s? b) If the bowling ball rolls into a pillow and stops in 1.5 s, calculate the average force on the pillow. c) What average Force does the pillow exert on the vectors required. 30 points ball. SKETCHES witharrow_forward
- 1. Which of the following statements is/are TRUE? a. The coefficient of restitution can take up a value greater than 1. b. The center of mass can be located outside the object, especially those with curved structures. c. The initial momentum of a moving body is directly proportional to the force applied and to the duration of its application. d. The final velocities of two colliding objects can be calculated if the coefficient of restitution is given along with the objects' initial velocities.arrow_forward1) A 100 g cart initially moving at +0.5 m/s collides elastically from a stationary 180 g cart. a) Using the equation in the theory, calculate the final velocity of the 100 g cart. b) Calculate the change in the momentum of the 100 g cart. c) Since this is an elastic collision, total momentum must be conserved. Using your answer for part b, calculate the final velocity of the 150 g cart.arrow_forward(a) What is the mass of a large ship that has a momentum of 1.40 x 109 kg-m/s, when the ship is moving at a speed of 38.0 km/h? 1.327 X kg (b) Compare the ship's momentum to the momentum of a 1400 kg artillery shell fired at a speed of 1300 m/s. P ship 769.23 Pshell Additional Materials MReadingarrow_forward
- 4. Define and illustrate a general collision of two objects in two-dimensional space. Please define the conservation of total momentum and energy of the system in each direction.arrow_forward21arrow_forwardSC 24: Module 4 Assignment Booklet 48 For questions 17 to 21, read each question carefully. Decide which of the choices BEST answers the question. Place your answer in the blank space given. 17. Two vehicles with the same mass and travelling the same speed in opposite directions hit head on. What is the total momentum immediately after the collision? A. zero B. double that of each car C. one half that of each car D. four tirnes that of each car Use the following diagram to answer questions 18 and 19. Car B Car A nt Bookl ence 24arrow_forward
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