PHY 132 - e_m of the Electron worksheet

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Arizona State University *

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132

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Physics

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Dec 6, 2023

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pdf

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4

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1 E / M O F T H E E L E C T R O N – W O R K S H E E T Name: Andrew Crist Partners: Hunter, Nahom, Zainab TA: Rekha Joshi DATA & ANALYSIS Measuring the Radius of the Coil Diameter D x : .29 (unit: m) Diameter D y : .295 (unit: m) D ave : .2925 (unit: m) Radius of the coil : .14625 (unit: m) Part 1 - Measuring e/m (Constant Voltage) Accelerating Voltage V acc = 200 (unit: V) Electron Orbit Radius r (in m) Coil Current I 0 (in A) Coil Current I 180 (in A) 0.055 1.02 1.04 0.050 1.14 1.14 0.045 1.26 1.26 0.040 1.46 1.47 0.035 1.66 1.60 0.030 1.94 1.84 Clean-up/sign-out (3): Data/Analysis (15/20): Graphs/Diagrams (20/10): Post Lab Q’s (20): Lab Report Total (88): Slope of B vs 1/r = 4.622*10^-5 unit: T/m e/m from the slope = 1.87*10^11 unit: C/kg % error = 6% Calculations F=eVB 2V/(rB^2) = 2(200)/((.14625)(4.622*10^-5)^2) Real e/m = 1.76*10^11. Find % error between two values by dividing the difference by the average. % error = ((1.87*10^11)- (1.76*10^11))/(((1.87*10^11)+(1.76*10^11))/2)
2 Part 2 - Measuring e/m (Constant Current) Coil Current ࠵? = 1.3 (unit: A) Magnetic Field ࠵? = 7.2*10^-3 (unit: T) Electron Orbit Radius r (m) Accelerating Voltage V 0 (in V) Accelerating Voltage V 180 (in V) 0.055 300 292 0.050 254 258 0.045 212 214 0.040 182 172 0.035 154 132 0.030 130 106 Calculations e/m = 2slope/B^2 = 2(8.5*10^4)/(7.2*10^-3)^2= 3.28*10^9 Slope of ࠵? vs ࠵? ! = 8.5*10^4 unit: V/m^2 e/m from the slope = 3.28*10^9 unit: C/kg % error = 192% Sketch the paths of the electron beam when you held the north & south ends of the magnet near the bulb. For each, show the position of the magnet relative to the beam and label the north & south poles.
3 POST LAB QUESTIONS 1. Explain what you observed when you held the magnet close to the bulb. Did only the beam’s radius change, or did something else change, too? Why was the beam deflected in this way? While the radius did change, the direction of the magnet also changed. The beam was deflected away because the beam is made up of electrons and electrons are affected by magnetic fields. 2. How fast were the electrons traveling after leaving the electron gun? Assume an accelerating voltage of 252.877 V. To earn credit for this question, show your work with units and express your final answer as a percentage of the speed of light, ࠵? = 3 × 10 ! ࠵?/࠵? . eV = .5mV^2 V^2 = eV / .5m V = sqrt(2eV/m) V = sqrt(2(1.6*10^-19)(252.877)/(9.109*10^-31)) V = 9.425*10^6 m/s or 1.57% the speed of light 3. Why do we rotate the apparatus 180 o and repeat the experiment? Rotating the coil helps account for any interferences from nearby magnetic fields. By rotating the apparatus while collecting data, we can cancel out those interferences by collecting their inputs from both directions. This leaves us with data only representing the apparatus. 4. When traveling between the Earth and Mars, future astronauts will be exposed to radiation from cosmic rays, solar flares, etc. What might a team of savvy engineers use to protect humans from high- energy charged particles on their journey to the red planet? (this is an open-ended question – feel free to get creative… but remember to consider the mass limitations imposed by space travel). One potential solution is to implement both electromagnetic and physical layers to fully protect the astronauts. The outer layer could consist of a sheet of metal creating a magnetic field which would deflect the radiation. This sheet would be backed by a layer of liquid to help absorb any penetrating radiation.
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